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KiRa [710]
2 years ago
14

Find the slope.

Mathematics
2 answers:
podryga [215]2 years ago
5 0
Y=45x+30

x=months
y= fee
Basile [38]2 years ago
3 0

9514 1404 393

Answer:

  • slope: 45
  • y-intercept: 30
  • equation: y = 45x + 30

Step-by-step explanation:

The slope is the cost per month. (A slope is often expressed as a ratio: dollars per month, in this case.) The slope is 45.

The y-intercept is the value that obtains when the number of months (in this case) is zero. It is the activation fee, 30. The y-intercept is 30.

__

The equation in slope-intercept form is ...

  y = mx + b . . . . . where m is the slope and b is the y-intercept

Using the above numbers, the equation is ...

  y = 45x + 30

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Answer:

5x + 2x + 7x

Step-by-step explanation:


7 0
3 years ago
Really need you guys help on this problem... please help me
erma4kov [3.2K]
Here it is.. you need to calculate some numbers

3 0
3 years ago
What types of numbers are undefined when they are under a radical sign? If you were dealing with the number √-1, would it be def
Misha Larkins [42]
The square root of a a negative integer is imaginary.
It would still be a negative under a square root if you multiplied it by 2, therefor it will still be imaginary, or I’m assuming as your book calls it, undefined.
2•(sqrt-1) = 2sqrt-1

If you add a number to -1 itself, specifically 1 or greater it will become a positive number or 0 assuming you just add 1. In that case it would be defined.
-1 + 1 = 0
-1 + 2 = 1

If you add a number to the entire thing “sqrt-1” it will not be defined.
(sqrt-1) + 1 = 1+ (sqrt-1)

If you subtract a number it will still have a negative under a square root, meaning it would be undefined.
(sqrt-1) + 1 = 1 + (sqrt-1)

however if you subtract a negative number from -1 itself, you end up getting a positive number or zero. (Subtracting a negative number is adding because the negative signs cancel out).
-1 - -1 = 0
-1 - -2 = 1

If you squared it you would get -1, which is defined
sqrt-1 • sqrt-1 = -1

and if you cubed it, you would get a negative under a square root again, therefor it would be undefined.
sqrt-1 • sqrt-1 • sqrt-1 = -1 • sqrt-1 = -1(sqrt-1)

Sorry if this answer is confusing, I don’t have a scientific keyboard, I’ll get one soon.
8 0
3 years ago
If a jogger runs 2 miles and burns 185 calories, how many calories would he burn if he jogged 3 miles?
aliina [53]

The total amount of calories burnt in jogging 2 miles = 185 calories

We have to determine the number of calories burned in jogging 3 miles.

Firstly, we will determine the amount of calories burnt in jogging 1 mile. We will use unitary method to evaluate this.

So, the total amount of calories burnt in jogging 1 mile = 185 \div 2

= 92.5 calories

So, the amount of calories burnt in 3 miles = 3 \times 92.5

= 277.5 calories

Therefore, 277.5 calories are burned in jogging 3 miles.

6 0
3 years ago
Read 2 more answers
A proper fraction is converted to a decimal equivalent by dividing the denominator into the numerator. True
kondaur [170]

False, it's the other way around: you divide the numerator by the denominator.

For example, to evaluate \frac{8}{15} you divide 8 by 15:

\dfrac{8}{15} = 8\div 15 = 0.5\overline{3}

7 0
3 years ago
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