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Airida [17]
3 years ago
12

PLEASE HELP I FORGOT HOW TO DO THIS

Mathematics
1 answer:
kozerog [31]3 years ago
7 0
If I’m not mistaken your answer would be 240
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X=3/2, -5 is that what u are asking for
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Trig Cosine - <br>Find x to the nearest tenth.​
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48.3

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A mother is currently 7 times older than her son. In 2 years time, she will be 5 times older than her son.
shtirl [24]

Answer:

y=-x+7

Step-by-step explanation:

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PLEASE HURRY!! <br> simplify completely<br> show all work for full credit
Irina18 [472]

Answer:

4x^{3}

Step-by-step explanation:

<u>Given:</u>

(\frac{192x^{12}}{3x^{3}} )^{\frac{1}{3}}

<u>Apply exponent rule of distribution:</u>

\frac{(192x^{12})^{\frac{1}{3}}}{(3x^{3})^{\frac{1}{3}}}

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\\\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{(3x^{3})^{\frac{1}{3}}}

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\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{3^\frac{1}{3}x}}

<u>Simplify:</u>

4x^{3}

-> To explain this party since it is a bigger jump, 3^{\frac{1}{3}}x is on the top and the bottom, so it becomes a one. We are left with a four on the top, and using properties of exponents 4 - 1 = 3, explaining why we have x^{3} leftover too.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

3 0
3 years ago
1.17 A study of the effects of smoking on sleep patterns is conducted. The measure observed is the time, in minutes, that it tak
bearhunter [10]

Answer:

a.

\bar X_F=43.7

\bar X_{NF}=30.32

b.

S_F=16.9278

S_{NF}=7.12783

c.

Attached file

d.

Apparently the practice of smoking reduces the ability to fall asleep, demanding much more time in individuals who smoke, than in those who do not smoke.

Step-by-step explanation:

a, b) For the group of smoking individuals, the average time it takes to fall asleep and the standard deviation of those times is:

\bar X_F={\frac{1}{n} \sum_{i=1}^n x_i = 43.7

S_F=\sqrt{\frac{1}{n-1} \sum_{i=1}^n (x_i-\bar{x})^2}=16.9278

a, b) For the group of non-smoking individuals, the average time it takes to fall asleep and the standard deviation of those times is:

\bar X_{NF}={\frac{1}{n} \sum_{i=1}^n x_i = 30.32

S_{NF}=\sqrt{\frac{1}{n-1} \sum_{i=1}^n (x_i-\bar{x})^2}=7.12783

c. In the attached file you can see the diagram of points for the times, in the smoking and non-smoking groups.

d. Apparently the practice of smoking reduces the ability to fall asleep, demanding much more time in individuals who smoke, than in those who do not smoke.

Download pdf
6 0
3 years ago
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