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3 years ago

12

For parties of six or more, a restaurant adds a 20% gratuity (or tip). If a

1 answer:

adelina 88 [10]3 years ago

6 0

Answer: tThe total dinner bill with tip = $177.90

Step-by-step explanation:

Given: Dinner bill = $148.25

Tip percent = 20%= 0.20

Total dinner bill = Dinner bill + Tip percent × (Dinner bill)

Total dinner bill = $ (148.25+0.20×148.25)

Total dinner bill = $ (148.25(1.20))

Total dinner bill = $177.90

Hence, the total dinner bill with tip = $177.90

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The area of a playground is 336 yd2. The width of the playground is 5 yd longer than its length. Find the length and width of th

kondaur [170]

L=16
W=21

Set up a systems of equations:
x=length
y=width

xy=336
x+5=y

Use substitution to solve:
x(x+5)=336
x^2+5x=336

Solve using factoring:
x^2+5x-336=0
(x-16)(x+21)=0
x=16 and x= -21
Since length can't be negative, l=16

To find width, plug length into the first equation:
(16)y=336
y=21

So...
L=16
<span>W=21</span>

7 0

3 years ago

Read 2 more answers

Use the permutation formula below to find the number of outcomes when n = 5 and r = 2.

faltersainse [42]

$nPr = \frac{n!}{(n - r)!}$

$5P2 = \frac{5!}{(5 - 2)!} = \frac{5 \times 4 \times 3 \times 2 \times 1}{3 \times 2 \times 1} = 20$

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2 years ago

Which equation would best help solve the following problem?

forsale [732]

Your answer is <span>–4.9t^2 + 15t + 1 = 0

Hope this helps.

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6 0

3 years ago

Charlie reads quickly. He reads 1\dfrac371 7 3 1, start fraction, 3, divided by, 7, end fraction pages every \dfrac23 3 2 st

OLEGan [10]

<h2>Answer:</h2>

The number of pages he will read in one minute is:

$2\dfrac{1}{7}\ \text{pages}$

<h2>Step-by-step explanation:</h2>

It is given that:

Charlie reads $1\dfrac{3}{7}\ \text{pages}$ in every $\dfrac{2}{3}\ \text{minutes}$ .

We know that:

$1\dfrac{3}{7}=\dfrac{10}{7}$

This means that:

Charlie reads $\dfrac{10}{7}\ \text{pages}$ in every $\dfrac{2}{3}\ \text{minutes}$ .

This means that:

$\text{In}\ \dfrac{2}{3}\ \text{minutes he reads}\ \dfrac{10}{7}\ \text{pages}\\\\\text{Hence}$

$\text{In}\ 1\ \text{minute he will read}\ \dfrac{\dfrac{10}{7}}{\dfrac{2}{3}}\ \text{pages}$

$\text{In}\ 1\ \text{minute he will read}\ \dfrac{10\times 3}{7\times 2}\ \text{pages}$

Hence,

$\text{In}\ 1\ \text{minute he will read}\ \dfrac{15}{7}\ \text{pages}$

Hence,

$\text{In}\ 1\ \text{minute he will read}\ \dfrac{15}{7}\ \text{pages}$

$\text{In}\ 1\ \text{minute he will read}\ 2\dfrac{1}{7}\ \text{pages}$

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3 years ago

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Given: Circumscribed polygon ELPJ

34kurt

$P_{ELPJ} = EK+ES+LU+LK+PV+PU JS+JV \\ \Leftrightarrow P_{ELPJ} = 2EK + 2LU + 2PV + 2JS = 2 \times 2 + 2 \times 4 + 2 \times 1 + 2 \times 2 = 18$

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3 years ago