All categories

3 years ago

4) Jose paid $4.98 in sales tax on an item that cost $62 before tax.

Mathematics

2 answers:

Llana [10]3 years ago

8 0

Answer:

net is before tax

gross is after

Lynna [10]3 years ago

4 0

Answer:

≈ $2.25

Step-by-step explanation:

This can be solved in two different ways.

1. Use ratios:

4.98/62 = x/28
x = 4.98*28/62
x ≈ $2.25

2. Find the tax percent:

4.98/62*100% = 8.03%

And apply this to $28

$28*8.03/100 ≈ $2.25

You might be interested in

(5x2 + 4x + 3) - (2x2 - 2x + 5)

Setler [38]

Answer:

3x^2+6x-2

Step-by-step explanation:

(5x2 + 4x + 3) - (2x2 - 2x + 5)

5x^2+4x+3-2x^2+2x-5

3x^2+6x-2

7 0

3 years ago

2. It’s time for Ronda to start repaying her student loans, which are amortized over the next 10 years. Her first month’s paymen

grigory [225]

Based on the amount that she paid in the first month, the amount Ronda will pay for the next month is $396.

When a loan is amortized, it means that one can pay it off by paying the same amount every period until they would have paid off both the loan and the associated interest.

The amortized amount contains:

A portion going towards the principal(debt )
A portion going towards the interest accumulated.

In conclusion, as the amount is the same every time, Ronda will have to pay the same amount of $396 the next month.

Find out more at brainly.com/question/12256592.

7 0

3 years ago

The ratio of students to adults on a field trip is 8 to 1. Which table correctly shows this ratio for each grade?

elena-14-01-66 [18.8K]

Answer:

The table C correctly shows the ratio 8:1 for each grade

Step-by-step explanation:

Let

x ----> the number of students

y ----> the number of adults

we know that

$\frac{x}{y}=\frac{8}{1}$

Verify each table

Table A

grade 6

$\frac{96}{88}=\frac{8}{1}$

Multiply in cross

$96(1)=8(88)$ ----> is not true

Table B

grade 6

$\frac{96}{104}=\frac{8}{1}$

Multiply in cross

$96(1)=8(104)$ ----> is not true

Table C

grade 6

\frac{96}{12}=\frac{8}{1}

Multiply in cross

$96(1)=8(12)$

$96=96$ ----> is true

grade 7

$\frac{120}{15}=\frac{8}{1}$

Multiply in cross

$120(1)=8(15)$

$120=120$ ----> is true

grade 8

\frac{136}{17}=\frac{8}{1}

Multiply in cross

$136(1)=8(17)$

$136=136$ ----> is true

therefore

The table C correctly shows the ratio 8:1 for each grade

Table D

grade 6

$\frac{96}{11}=\frac{8}{1}$

Multiply in cross

$96(1)=8(11)$ ----> is not true

3 0

3 years ago

Read 2 more answers

Solve the following system of equations algebraically for all values of a, b, and c.

kirill [66]

A is the answer to this question no doubt

6 0

3 years ago

Find the values of which satisfy the equation. 2 cos (2B+30°) = -√3 in the domain OP ≤B≤360°

PSYCHO15rus [73]

Answer:

60 and 90

Step-by-step explanation:

$2 \cos(2 \beta + 30) = - \sqrt{3}$

$\cos(2 \beta + 30) = - \frac{ \sqrt{3} }{2}$

$2 \beta + 30 = \cos {}^{ - 1} ( \frac{ - \sqrt{3} }{2} )$

First solution.

$2 \beta + 30 = 150$

$2 \beta = 120$

$\beta = 60$

Second solution

$2 \beta + 30 = 210$

$2 \beta = 180$

$\beta = 90$

5 0

2 years ago