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tekilochka [14]
3 years ago
11

The function f(t)=t^2+12t-18 represents a parabola. Part A: Rewrite the function in vertex form by completing the square. Show y

our work. Part B:Determine the vertex and indicate whether its a maximum or minimum on the graph. How do you know? Part C: Determine the axis of Symmetry
Mathematics
1 answer:
ale4655 [162]3 years ago
6 0
The function in vertex form is f(t) = (t+6)^{2} -54 (refer to your other post I solved it there).
The general form of quadratic equations in vertex form is f(x) = a(x-h)^{2} +k, where (h, k) is the vertex of the parabola.
Here, a = 1, h = -6 and k = -54
Therefore, the vertex is (-6, -54) and it is a maximum because a = 1 is postive.
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Answer:

(0, -3)

Step-by-step explanation:

y = 3x - 3

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In the solution to the system of equations, y is the same number for both of those functions. So 3x - 3 = x - 3.

Then solve for x:

3x - 3 = x - 3

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Now that you have x, substitute it in one of the equations:

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