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tekilochka [14]
3 years ago
11

The function f(t)=t^2+12t-18 represents a parabola. Part A: Rewrite the function in vertex form by completing the square. Show y

our work. Part B:Determine the vertex and indicate whether its a maximum or minimum on the graph. How do you know? Part C: Determine the axis of Symmetry
Mathematics
1 answer:
ale4655 [162]3 years ago
6 0
The function in vertex form is f(t) = (t+6)^{2} -54 (refer to your other post I solved it there).
The general form of quadratic equations in vertex form is f(x) = a(x-h)^{2} +k, where (h, k) is the vertex of the parabola.
Here, a = 1, h = -6 and k = -54
Therefore, the vertex is (-6, -54) and it is a maximum because a = 1 is postive.
You might be interested in
1.F(3)=-3x+2<br> 2.f(0)=-3x+2<br> 3.f(-2)=-3x+2
Firlakuza [10]

Answer:

1) -3(3) + 2 = -7

2) -3(0) + 2 = 2

3) -3(-2) + 2 = 8

3 0
2 years ago
School x and y are in a comepetition. School x has 8 more points than school y and 3 times more points as school y . How many po
lara [203]

Answer:  School Y has 4 points and School X has 12 points.

Explanation:

Let the number of points School Y has be x

Let the number of points School X has be 3x

According to question, we get

3x-x=8\\\\2x=8\\\\x=\frac{8}{2}\\\\x=4

So, the number of point School Y has 4.

and number of points School X has

3x=3\times 4=12

Hence, School Y has 4 points and School X has 12 points.



6 0
3 years ago
You and a friend tutor for a total of 12 hours. Use the tape diagram to find how many hours you tutor.
kirill [66]

Answer: YOU TUTOR 9 HOURS

Step-by-step explanation: EACH BOX REPRESENTS 3 HOURS I THINK, SO YOU TUTOR NINE HOURS AND YOUR FRIEND TUTORS 3 HOURS.

3X3=9

1X3=3

5 0
2 years ago
Figure B is a scaled copy of Figure A.Select all of the statements that must be true:
KatRina [158]

Answer:

B) Figure B has the same number of edges as Figure A

D) Figure B has the same number of angles as Figure A

E) Figure B has angles with the same measures as Figure A

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem

If Figure B is a scaled copy of Figure A

then

Figure A and Figure B are similar

therefore

<u><em>The statements that must be true are</em></u>

B) Figure B has the same number of edges as Figure A

D) Figure B has the same number of angles as Figure A

E) Figure B has angles with the same measures as Figure A

6 0
3 years ago
Can we obtain a diagonal matrix by multiplying two non-diagonal matrices? give an example
polet [3.4K]
Yes, we can obtain a diagonal matrix by multiplying two non diagonal matrix.

Consider the matrix multiplication below

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]   \left[\begin{array}{cc}e&f\\g&h\end{array}\right] =  \left[\begin{array}{cc}a e+b g&a f+b h\\c e+d g&c f+d h\end{array}\right]

For the product to be a diagonal matrix,

a f + b h = 0 ⇒ a f = -b h
and c e + d g = 0 ⇒ c e = -d g

Consider the following sets of values

a=1, \ \ b=2, \ \ c=3, \ \ d = 4, \ \ e=\frac{1}{3}, \ \ f=-1, \ \ g=-\frac{1}{4}, \ \ h=\frac{1}{2}

The the matrix product becomes:

\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}\frac{1}{3}&-1\\-\frac{1}{4}&\frac{1}{2}\end{array}\right] = \left[\begin{array}{cc}\frac{1}{3}-\frac{1}{2}&-1+1\\1-1&-3+2\end{array}\right]= \left[\begin{array}{cc}-\frac{1}{6}&0\\0&-1\end{array}\right]

Thus, as can be seen we can obtain a diagonal matrix that is a product of non diagonal matrices.
8 0
3 years ago
Read 2 more answers
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