1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
frutty [35]
3 years ago
5

Solve the following inequality 0.5z-0.1 >0.2

Mathematics
2 answers:
Paraphin [41]3 years ago
8 0

Answer: z>0.6

Step-by-step explanation:

You isolate the variable by dividing each side by factors that don’t contain the variable.

The answer is verified it came from Math-way .

QveST [7]3 years ago
3 0

Answer:

z≥0.6

Step-by-step explanation:

You might be interested in
What is the sign of a.
posledela

As a = 0 , there is no sign . Its only 0. Thus the answer is (c)

6 0
3 years ago
Why did I get this question wrong?
lord [1]

Step-by-step explanation:

∫₀³⁰ (r/V C₀ e^(-rt/V)) dt

If u = -rt/V, then du = -r/V dt.

∫ -C₀ e^u du

-C₀ ∫ e^u du

-C₀ e^u + C

-C₀ e^(-rt/V) + C

Evaluate between t=0 and t=30.

-C₀ e^(-30r/V) − -C₀ e^(-0r/V)

-C₀ e^(-30r/V) + C₀

C₀ (-e^(-30r/V) + 1)

I got the same answer.  Try changing the lowercase v to an uppercase V.

4 0
3 years ago
CAN YOU HELP ME ND WHO LOVE BILLIE ELISHIE
Alla [95]
I don’t like billies music but i like her as a person
8 0
2 years ago
Read 2 more answers
The perimeter of the figure below is 54.9 in. Find the length of the missing side.
Hoochie [10]
7.3in have a nice dayyyyyy
8 0
3 years ago
What eigen value for this matix <br> (1 -2)<br> (-2 0)
natali 33 [55]

You find the eigenvalues of a matrix A by following these steps:

  1. Compute the matrix A' = A-\lambda I, where I is the identity matrix (1s on the diagonal, 0s elsewhere)
  2. Compute the determinant of A'
  3. Set the determinant of A' equal to zero and solve for lambda.

So, in this case, we have

A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]

The determinant of this matrix is

\left|\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right| = -\lambda(1-\lambda)-(-2)(-2) = \lambda^2-\lambda-4

Finally, we have

\lambda^2-\lambda-4=0 \iff \lambda = \dfrac{1\pm\sqrt{17}}{2}

So, the two eigenvalues are

\lambda_1 = \dfrac{1+\sqrt{17}}{2},\quad \lambda_2 = \dfrac{1-\sqrt{17}}{2}

5 0
2 years ago
Read 2 more answers
Other questions:
  • PLEASE ANSWER WILL GIVE BRANIEST AND A KISS :3
    15·1 answer
  • Another word for "all the way around, arc-lengthwise"...
    15·2 answers
  • The graph of g(x) is f(x) translated to the left 8 units and up 2 units. What is the function rule for g(x) given f(x) = x²?
    11·1 answer
  • If 2X +3 equals 11 what is 4X hint solve for x first
    10·1 answer
  • What Is The Answer????​
    15·1 answer
  • What part of 29 is 36?
    8·1 answer
  • Find the indefinite integral using the substitution x = 10 sin(θ). (Use C for the constant of integration.) 1 (100 − x2)3/2 dx
    8·1 answer
  • How many solutions does 13(y+3)=13y
    15·1 answer
  • Jamie Nolan purchased new cabinets for $12,640: laminate flooring for $4,560; countertops for
    11·1 answer
  • (-1) power 50 is what
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!