Answer:
The possible length of the triangle =
1) (1inches, 196inches)
2) (2incheq, 98inches)
3) (4inches , 49 inches)
4) (7 inches , 28 inches)
Step-by-step explanation:
We are told the above Triangle is not an Isosceles Triangle
Hence, we assume it is a right angle triangle
The area of a triangle is = 1/2 × Base × Height
= let us represent Base and Height = x
Hence:
1/2 × x × x = 98
x² /2 = 98
Cross Multiply
x² = 98 × 2
x² = 196
Step 2
We find the factors of 196
1× 196 = 196 (1, 196)
2 × 98 = 196 (2, 98)
4 ×49 = 196 (4, 49)
7 × 28 = 196 (7, 28)
Therefore, all the possible length of the triangle =
1) (1inches, 196inches)
2) (2incheq, 98inches)
3) (4inches , 49 inches)
4) (7 inches , 28 inches)
The colors on the image should match the correct blank spots on the proof. Please let me know if you disagree or is confused by my choices.
Okay first you have to divide
2 goes into 3
3/2
2 fits into 3 once
1 and the left over is 1 so
1 1/2
Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
