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3 years ago

What is the area of this triangle? enter your answer in the box.

Mathematics

2 answers:

adoni [48]3 years ago

8 0

Answer:

I can't do the area but area of a triangle is

A of triangle = h×b over 2

h = hieght of the triangle

b= base of the triangle

11111nata11111 [884]3 years ago

6 0

Answer:

Step-by-step explanation:

finished quiz and got the correct answer

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Divide 1/7 divided by 6

ArbitrLikvidat [17]

Answer:

1/42

Step-by-step explanation:

1/7 ÷ 6/1

1 x 1 = 1

------------

7 x 6 = 42

1/42

already simplified to the fullest

hope that helps!

6 0

2 years ago

The area of the rectangle below is __sq. units.<br> 5<br> 16

SIZIF [17.4K]

Answer:

Step-by-step explanation:

To find the area of a rectangle, times the length and the breadth together. So, it would be 16×5=80. option C is 80.

4 0

2 years ago

Read 2 more answers

NEED AN ANSWER ASAP How are the terms in parentheses affected when multiplied by a negative coefficient when the distributive pr

Anna [14]

The Distributive Property is an algebra property which is used to multiply a single term and two or more terms inside a set of parentheses.

The Distributive Property tells us that we can remove the parentheses if the term that the polynomial is being multiplied by is distributed to, or multiplied with each term inside the parentheses.

If a number outside the parentheses has a negative sign then the first and simplest way is to change each positive or negative sign of the terms that were inside the parentheses. Negative or minus signs become positive or plus signs. Similarly, positive or plus signs become negative or minus signs.

5 0

3 years ago

Which is the interval notation represent the domain?

Kazeer [188]

Answer:

The first choice, $(-\infty, 7) \cup (7, \infty)$ .

Step-by-step explanation:

The dashed vertical line is a vertical asymptote. The x-coordinate of all points on this vertical asymptote are equal to 7. In other words, when the x-value of a point on the graph approaches $7$ , its y-value approaches infinity (or negative infinity.)

Either way, the graph is not defined for $x = 7$ . The point $7$ should thus be excluded from the domain of the graph.

The graph is apparently defined for all other x-values. The domain of the function should thus be all real numbers with the exception of $x = 7$ . Here's how to write that in interval notation:

The set of all real numbers can be expressed as the interval $(-\infty, \infty)$ . Note that infinity $\infty$ (or $(- \infty)$ itself isn't a real number. The round brackets indicate that both endpoints are excluded from the from the interval.
The set of all real numbers less than (not equal to) $7$ is $(-\infty,7 )$ (both ends are excluded.) The set of all real numbers greater than (not equal to) $7$ is $(7, \infty)$ .
The set of all real numbers that is not equal to $7$ is the union of all real numbers less than $7$ and all real numbers greater than $7$ . The union operator $\cup$ connects two intervals.