We know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side (Triangle Inequality Theorem)
Let
A------> Lincoln, NE
B------> Boulder, CO
C------> third city
we know that
in the triangle ABC
AB=500 miles
BC=200 miles
AC=x
Applying the Triangle Inequality Theorem
1) 500+200 > x------> 700 > x------> x < 700 miles
2) 200+x > 500----> x > 500-200------> x > 300 miles
the solution for x is
300 < x < 700
the interval is------> (300,700)
the possible distances, d, in miles, between Lincoln, NE, and the third city, are in the range between 300 and 700 miles
2.1 m²
so um it's a regular hexagon since all of its side lengths are equal.
Mark brainliest please
Answer:
x = 9±sqrt(7)
Step-by-step explanation:
3(x-9)^2 =21
Divide each side by 3
3/3(x-9)^2 =21/3
(x-9)^2 =7
Take the square root of each side
sqrt((x-9)^2) =±sqrt(7)
x-9 =±sqrt(7)
Add 9 to each side
x = 9±sqrt(7)
Answer:
it's D
Step-by-step explanation:
i just know what I am talking about
He could plant 105 seedlings in 70 minutes.
70 / 8 = 8.75 * 12 = 105 seedlings
I hope this helps :)
