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3 years ago

Please Help Me With Functions!!!!!!

Mathematics

1 answer:

denpristay [2]3 years ago

3 0

Answer:

I don't know how to do it the question

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A screwdriver set has a selling price per unit of $27.95. It also has fixed costs of $837,500, variable costs per unit of $3.25

Sergio [31]

A) $1,016,250 is the right answer

3 0

3 years ago

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Can someone help me get extra credit in my class? Geometry question easy

Irina-Kira [14]

Answer:

the last one is true

Step-by-step explanation:

sin R=PQ/PR=TS/TR

4 0

3 years ago

A clinical trial was conducted to test the effectiveness of a drug for treating insomnia and older subjects before treatment 14

RideAnS [48]

Answer:

99% confidence interval estimate of the mean weight time for a population with drug treatments

(79.11 , 112.69)

Step-by-step explanation:

Step(i):-

Given data mean of the Population = 104 minutes

Given sample size 'n' =14

Mean of the sample(x⁻) = 95.9 minutes

Given Standard deviation = 24.4 minutes

Step(ii):-

99% confidence interval estimate of the mean weight time for a population is determined by

$(x^{-} - Z_{0.01} \frac{S.D}{\sqrt{n} } , x^{-} +Z_{0.01} \frac{S.D}{\sqrt{n} })$

$(95.9 - 2.576\frac{24.4}{\sqrt{14} } , 95.9+2.576\frac{24.4}{\sqrt{14} })$

On calculation , we get

(95.9 -16.79 , 95.9 +16.79)

(79.11 , 112.69)

Conclusion:-

99% confidence interval estimate of the mean weight time for a population with drug treatments

(79.11 , 112.69)

7 0

3 years ago

Simplify 3 x + 6 x 2 - 5 x - x 2 .

Anastasy [175]

Pretty sure it’s 5x^2 - 2x

5 0

3 years ago

Students in a class were surveyed about the number of children in their families. The results of the survey are shown in the tab

ki77a [65]

Answer:

1/5

Step-by-step explanation:

Since the surveys are chosen with replacement (the first one is replaced before the second is chosen), the events are independent. This means that the probability of both together is the product of each event's probability.

The probability of choosing a survey that indicates 4 children in the family is 8/60, since there are 8 surveys with 4 children out of a total of (9+18+22+8+3) = 60 surveys.

The probability of choosing a survey that indicates 1 child is 9/60, since there are 9 surveys with 1 child out of a total of 60.

Together this gives us

8/60(9/60) = 72/360 = 1/5

3 0

4 years ago

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