Answer:
The expression is not completely factored.
Step-by-step explanation:
The expression of
can be broken up into two binomials:
![[x - 2][x + 2]](https://tex.z-dn.net/?f=%5Bx%20-%202%5D%5Bx%20%2B%202%5D)
Together, you have this:
![3[x - 2][x + 2]](https://tex.z-dn.net/?f=3%5Bx%20-%202%5D%5Bx%20%2B%202%5D)
** There is alot of missing information to this question, but at least you know how to work this out.
I am joyous to assist you anytime.
In the point (x, y), if x=0, then the point is on the y axis.
If y=0, the point is on the x axis
If both x and y are positive (greater than 0), the point is in quadrant 1
If x is negative (less than 0) and y is positive (greater than 0), the point is in quadrant 2
If both x and y are negative, the point is in quadrant 3
If x is positive and y is negative, the point is in quadrant 4
Taking (-3, 2), since 3 has a - sign before it (and nothing else), it is negative. Since the x value comes first, this means that x is negative. Since it simply states "2" for the y value, it is positive. As x is negative and y is positive, we know that the point is in quadrant 2.
I challenge you to do this on your own - good luck, and feel free to ask with further questions!
Well, if one face has an area of 81 square centimeters, then that means that each side of the square is 9 centimeters. The formula to find volume is

, so 9^3 = 729.
In short, your answer would just be 729 centimeters
Hope this helped!!!
It would be the first one because each orange costs $0.34
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 