10 Ne:
1s², 2s², 2p⁶
Answer C
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Answer:
The parcial pressure of N₂ in the mixture is 1.24 atm.
Explanation:
The pressure exerted by a particular gas in a mixture is known as its partial pressure. So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:
PT = PA + PB
This relationship is due to the assumption that there are no attractive forces between the gases.
In this case:
PT=PHe + PNe + PN₂
You know:
- PT= 1.943 atm
- PHe= 0.137 atm
- PNe= 0.566 atm
- PN₂= ?
Replacing:
1.943 atm= 0.137 atm + 0.566 atm + PN₂
Solving:
1.943 atm= 0.703 atm + PN₂
1.943 atm - 0.703 atm= PN₂
1.24 atm= PN₂
<u><em>The parcial pressure of N₂ in the mixture is 1.24 atm.</em></u>
Answer:
For mole conversion always remember 1 mole of compound = molar mass of compound.
Ex. 2 moles H20 to grams
2mol H2O x 18 g / 1mol H20
For molecules use Avogadro's number like moles multiplied to 6.022x10²³ answer will be in molecules.
Explanation:
Answer:
Final molarity = 6 M
Explanation:
Given data:
Initial volume = 0.50 L
Initial molarity = 12 M
Final volume = 1 L
Final molarity = ?
Solution:
Formula:
M₁V₁ = M₂V₂
M₁ = Initial molarity
V₁ = Initial volume
M₂ = Final molarity
V₂ = Final volume
Now we will put the values.
12 M × 0.50 L = M₂ × 1 L
6 M.L = M₂ × 1 L
M₂ = 6 M.L / 1L
M₂ = 6 M
Answer:
In an electrophilic aromatic substitution (Friedel Crafts alkylation) first in the monoalkylation of the 1,4-dimethoxybenzenethe the methoxy groups redirects the substitution for ortho-para positions with respect to the electrophile that is going to enter (alkyl group) this is due to the increase in electron density in that position, that is , to the inductive effect.
According to the second incoming alkyl group there would be 3 positions available, from which it will choose the meta position in relation to the second methoxy group, since the alkyl group is a weak activator of the ortho meta positions and coincides with the position to which it redirects the second methoxy group.