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hammer [34]
3 years ago
13

The work done by effort is called​

Chemistry
1 answer:
Travka [436]3 years ago
5 0

Answer:

load

Explanation:

the load is the work done by the effort on the machine

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Neon is an inert gas and has the atomic number of 10. Which of the following correctly depicts its electron configuration? 1s22d
Cloud [144]
10 Ne:

1s², 2s², 2p⁶

Answer C

hope this helps!
8 0
3 years ago
A mixture of He, Ne, and N2 gases has a pressure of 1.943 atm. If the pressures of He and Ne are 0.137 atm and 0.566 atm, respec
Ad libitum [116K]

Answer:

The parcial pressure of N₂ in the mixture is 1.24 atm.

Explanation:

The pressure exerted by a particular gas in a mixture is known as its partial pressure. So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

PT = PA + PB

This relationship is due to the assumption that there are no attractive forces between the gases.

In this case:

PT=PHe + PNe + PN₂

You know:

  • PT= 1.943 atm
  • PHe= 0.137 atm
  • PNe= 0.566 atm
  • PN₂= ?

Replacing:

1.943 atm= 0.137 atm + 0.566 atm + PN₂

Solving:

1.943 atm= 0.703 atm + PN₂

1.943 atm - 0.703 atm= PN₂

1.24 atm= PN₂

<u><em>The parcial pressure of N₂ in the mixture is 1.24 atm.</em></u>

4 0
3 years ago
What is the easiest way to do mole conversions i.e. to grams, molecules, and formula units?
CaHeK987 [17]

Answer:

For mole conversion always remember 1 mole of compound = molar mass of compound.

Ex. 2 moles H20 to grams

2mol H2O x 18 g / 1mol H20

For molecules use Avogadro's number like moles multiplied to 6.022x10²³ answer will be in molecules.

Explanation:

6 0
3 years ago
When 0.50 liter of a 12m solution is diluted to 1.0 liters, the molarity of the new solution is ____
Akimi4 [234]

Answer:

Final molarity  = 6 M

Explanation:

Given data:

Initial volume = 0.50 L

Initial molarity = 12 M

Final volume = 1 L

Final molarity = ?

Solution:

Formula:

M₁V₁ = M₂V₂

M₁ = Initial molarity

V₁ = Initial volume

M₂ = Final molarity

V₂ = Final volume

Now we will put the values.

12 M × 0.50 L = M₂ ×  1 L

6 M.L = M₂ ×  1 L

M₂ = 6 M.L / 1L

M₂ = 6 M

6 0
4 years ago
Explain the regiochemistry of the Friedel-Crafts alkylation of 1,4-dimethoxybenzene. There are three positions available for the
defon

Answer:

In an electrophilic aromatic substitution (Friedel Crafts alkylation) first in the monoalkylation of the 1,4-dimethoxybenzenethe the methoxy groups redirects the substitution for ortho-para positions with respect to the electrophile that is going to enter (alkyl group) this is due to the increase in electron density in that position, that is , to the inductive effect.

According to the second incoming alkyl group there would be 3 positions available, from which it will choose the meta position in relation to the second methoxy group, since the alkyl group is a weak activator of the ortho meta positions and coincides with the position to which it redirects the second methoxy group.

7 0
3 years ago
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