The concentration of solution : 0.2 M
<h3>Further explanation</h3>
Given
5.6 g Potassium hydroxide(KOH)
500 ml of solution = 0.5 L
Required
The concentration
Solution
Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution
MW KOH = 39+16+1=56 g/mol
mol solute(KOH) :
= mass : MW KOH
= 5.6 : 56 g/mol
= 0.1
Molarity :
= 0.1 : 0.5
= 0.2 M
where is the diagram?
without the diagram i can't help
The mole fraction of urea in a solution that contain 2.1 mol Urea and 4.4 mole of water is 0.32
calculation
mole fraction = moles of urea/ total mole
moles of urea = 2.1 mole
calculate the total mole
= 2.1 mole + 4.4 mole = 6.5
Mole fraction is therefore = 2.1/.6.5 = 0.32