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____ [38]
3 years ago
6

Five times the second of three consecutive odd integers is thirteen less than three times the sum of the first and third integer

s. Find the largest odd number.
Mathematics
1 answer:
viva [34]3 years ago
8 0

Answer: 15

Step-by-step explanation:

suppose;  three consecutive odd integers are x; x + 2; x+ 4 (x is a odd integer)

because Five times the second of three consecutive odd integers is thirteen less than three times the sum of the first and third integers

=> 5(x + 2) = 3( x +x +4) - 13

<=> 5x + 10 = 6x + 12 - 13

<=>6x - 5x = 10 + 13 - 12

<=> x = 11

=> the largest odd number is 11 + 4 = 15

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The given equation has no solution when K is any real number  and k>12

We have given that

3x^2−4x+k=0

△=b^2−4ac=k^2−4(3)(12)=k^2−144.

<h3>What is the condition for a solution?</h3>

If Δ=0, it has 1 real solution,

Δ<0 it has no real solution,

Δ>0 it has 2 real solutions.

We get,

Δ=k^2−144 here Δ is not zero.

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manuel wanted to put a brick walkway through his backyard from door to bbq area. the walkway is going to be 6 yards long. so far
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155 inches

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9514 1404 393

Answer:

  12. (x, D, E, F) = (8, 38°, 75°, 67°)

  13. (x, P, Q, R) = (13, 126°, 30°, 24°)

Step-by-step explanation:

The sum of angles in a triangle is 180°. We choose to write the equations assuming all measures are degrees.

12. (5x -2) +(9x +3) +(11x -21) = 180

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  x = 8 . . . . . . . . . divide by 25

Then the angle measures are ...

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  ∠E = 9(8) +3 = 75°

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__

13. (10x -4) +(4x -22) +(x +11) = 180

  15x = 195 . . . . . . . . . . add 15, simplify

  x = 13 . . . . . . . . . divide by 15

Then the angle measures are ...

  ∠P = 10(13) -4 = 126°

  ∠Q = 4(13) -22 = 30°

  ∠R = 13 +11 = 24°

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3 years ago
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