Five times the second of three consecutive odd integers is thirteen less than three times the sum of the first and third integer
1 answer:
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Answer:
a₈ = 37
Step-by-step explanation:
The given arithmetic sequence is: 3, 8, 13, 18, 23, . . .
The recursive formula for the sequence is:
Here, represents the
of the sequence.
And, represents the
of the sequence.
'+5' denotes that '5' is added to the term to get the
term. In other words, the difference between two consecutive numbers in the sequence is 5.
Now, we are asked to find a₈ i.e., n =8.
Substituting in the recursive formula we get: a₈ = a₍₈₋ ₁₎ + 5 = a₇ + 5.
So, to determine a₈ we need to know a₇. From the sequence we see that a₅ = 23.
⇒ a₆ = 23 + 5 = 28.
⇒ a₇ = 28 + 5 = 32.
⇒ a₈ = 32 + 5 = 37.
Therefore, the term of the sequence is 37.
Answer:
x = 9.8
Step-by-step explanation:
to find x, use pythagorean theorem
⇒ 9.8