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Katen [24]
2 years ago
10

A rectangle has a length of 5x - 15 and a length of 2x + 7. What is the area of the rectangle?​

Mathematics
1 answer:
Sergeu [11.5K]2 years ago
3 0
2(5x-15) + 2(2x+7) =0
10x-30+4x+14 = 0
14x = 16
x = 8/7
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A trapezoid has an area of 36 square feet. If its height is 8, and one base is 4, what is the length of the other base?
Georgia [21]

Answer:

5

Step-by-step explanation:

A=a+b/2 x h

4 = a

5 = b

8 = h

4 + 5 / 2 = 4.5

4.5 x 8 = 36

So the other base length is 5

5 0
2 years ago
How can you get 3/3 -1/6?
cluponka [151]

9514 1404 393

Answer:

  5/6

Step-by-step explanation:

Addition or subtraction of fractions requires a common denominator. The value 3/3 can be multiplied by 2/2 to give 6/6, which has the same denominator as the other fraction.

  \dfrac{3}{3}-\dfrac{1}{6}=\dfrac{3\cdot2}{3\cdot2}-\dfrac{1}{6}\\\\=\dfrac{6}{6}-\dfrac{1}{6}=\dfrac{6-1}{6}=\boxed{\dfrac{5}{6}}

5 0
3 years ago
I really need help big time thank you
Hunter-Best [27]
1) 2x² -5x+12
2) x² +7x+10
3) 3x² +5x-2
5 0
3 years ago
Hello homework due tomorrow I will give 15points
antoniya [11.8K]
Im pretty sure i can help you out on this one
4 0
3 years ago
How do you solve this?
k0ka [10]
x^2-3x-4=0\\\\x^2-2x\cdot\frac{3}{2}=4\ \ \ /+(\frac{3}{2})^2\\\\x^2-2x\cdot\frac{3}{2}+(\frac{3}{2})^2=4+(\frac{3}{2})^2\\\\(x-\frac{3}{2})^2=4+\frac{9}{4}\\\\(x-\frac{3}{2})^2=\frac{16}{4}+\frac{9}{4}\\\\(x-\frac{3}{2})^2=\frac{25}{4}\\\\x-\frac{3}{2}=\pm\sqrt\frac{25}{4}

x-\frac{3}{2}=\pm\frac{\sqrt{25}}{\sqrt4}\\\\x-\frac{3}{2}=\pm\frac{5}{2}\\\\x-\frac{3}{2}=-\frac{5}{2}\ or\ x-\frac{3}{2}=\frac{5}{2}\\\\x=-\frac{5}{2}+\frac{3}{2}\ or\ x=\frac{5}{2}+\frac{3}{2}\\\\x=-\frac{2}{2}\ or\ x=\frac{8}{2}\\\\x=-1\ or\ x=4
5 0
2 years ago
Read 2 more answers
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