Answer:
see the procedure
Step-by-step explanation:
we have

where
c -----> the cost in dollars
g ----> the number gallons of gas purchased
1) For g=1 gal
substitute the value of g in the equation and solve for c


The pair (1,2.95) fit the relationship
2) For g=3 gal
substitute the value of g in the equation and solve for c


The pair (3,8.85) fit the relationship
3) For g=5 gal
substitute the value of g in the equation and solve for c


The pair (5,14.75) fit the relationship
4) For c=$20.65
substitute the value of c in the equation and solve for g



The pair (7,20.65) fit the relationship
Pi is actually one of the letters of the Greek alphabet, but it is most known in the math field as the ratio between the circumference of a circle and the circle's diameter.
There is no exact measure of pi, as it does not terminate but it starts like:
3.14159265





--------------- In Pure Text Format --------------
Mass of the earth = 5.97 x 10^{24}
Mass of Venus = 4.87 x 10^{24}
Difference = (5.97 - 4.87) x 10^{24} = 1.1 x 10^{24} kg
Answer:
B. 4 and 6/10
Step-by-step explanation:
in order to find this answer i've always had a trick where i first off find an even number to divide these with and in this case that would be 4 and then the leftovers would be 6/10 and in this case your answer would be right there 4 and 6/10 but if needed to be simplified it would be 4 and 3/5
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have a good day!
This is a simple problem based on combinatorics which can be easily tackled by using inclusion-exclusion principle.
We are asked to find number of positive integers less than 1,000,000 that are not divisible by 6 or 4.
let n be the number of positive integers.
∴ 1≤n≤999,999
Let c₁ be the set of numbers divisible by 6 and c₂ be the set of numbers divisible by 4.
Let N(c₁) be the number of elements in set c₁ and N(c₂) be the number of elements in set c₂.
∴N(c₁) =

N(c₂) =

∴N(c₁c₂) =

∴ Number of positive integers that are not divisible by 4 or 6,
N(c₁`c₂`) = 999,999 - (166666+250000) + 41667 = 625000
Therefore, 625000 integers are not divisible by 6 or 4