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faust18 [17]
3 years ago
5

If 20.0 g acetylene is allowed to completely react with oxygen, how many grams of o2 are reacted? 2c2h2(g 5o2(g → 4co2(g 2h2o(g

acetylene
Chemistry
1 answer:
KATRIN_1 [288]3 years ago
7 0
The balanced chemical reaction is written as:

<span>2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)

We are given the amount of acetylene to be used in the reaction. This will be the starting point for the calculations.

20.0g C2H2 ( 1 mol / 26.04 g) ( 5 mol O2 / 2 mol C2H2 ) ( 32 g / 1 mol ) = 61.44 g O2 is needed</span>
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Magnesium (average atomic mass = 24.3050 amu) consists of three isotopes with masses 23.9850 amu, 24.9858 amu, and 25.9826 amu.
iris [78.8K]

Answer: The first isotope has a relative abundance of 79% and last isotope has a relative abundance of 11%

Explanation: Given that the average atomic mass(M) of magnesium

= 24.3050amu

Mass of first isotope (M1) = 23.9850amu

Mass of middle isotope (M2)=24.9858amu

Mass of last isotope(M3)= 25.9826amu

Total abundance = 1

Abundance of middle isotope = 0.10

Let abundance of first and last isotope be x and y respectively.

x+0.10+y =1

x = 0.90-y

M = M1 × % abundance of first isotope + M2 × % of middle isotope +M3 ×% of last isotope

24.03050= 23.985× x + 24.9858 ×0.10 + 25.9826×y

Substitute x= 0.90-y

Then

y = 0.11

Since y=0.11, then

x= 0.90-0.11

x=0.79

Therefore the relative abundance of the first isotope = 11% and the relative abundance of the last isotope = 79%

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Answer:

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Explanation:

From the question,

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make V' the subject of the equation

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