If 20.0 g acetylene is allowed to completely react with oxygen, how many grams of o2 are reacted? 2c2h2(g 5o2(g → 4co2(g 2h2o(g
acetylene
1 answer:
The balanced chemical reaction is written as:
<span>2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)
We are given the amount of acetylene to be used in the reaction. This will be the starting point for the calculations.
20.0g C2H2 ( 1 mol / 26.04 g) ( 5 mol O2 / 2 mol C2H2 ) ( 32 g / 1 mol ) = 61.44 g O2 is needed</span>
You might be interested in
19.864 meters would be the correct answer
Here's one! those spots are actually storms:)
Answer:
I believe the answer isT 2.
Explanation:
he formula for IMA of a first-class lever is effort-distance/resistance-distance.
Answer:
Yeah, Fine..
Explanation:
Answer:
2=2.28*10^5
3=3.98*10^3
4=5.76*10^3
