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faust18 [17]
3 years ago
5

If 20.0 g acetylene is allowed to completely react with oxygen, how many grams of o2 are reacted? 2c2h2(g 5o2(g → 4co2(g 2h2o(g

acetylene
Chemistry
1 answer:
KATRIN_1 [288]3 years ago
7 0
The balanced chemical reaction is written as:

<span>2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)

We are given the amount of acetylene to be used in the reaction. This will be the starting point for the calculations.

20.0g C2H2 ( 1 mol / 26.04 g) ( 5 mol O2 / 2 mol C2H2 ) ( 32 g / 1 mol ) = 61.44 g O2 is needed</span>
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Calculate the ph of sweater which has a hydrogen ion concentration of 1 times 10 to the power of 8
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Answer:

The pH of the sweater containing Hydrogen ion concentration

[H^{+}]=1\times 10^{-8} is

<u>8</u>

<u></u>

Explanation:

pH = It is the negative logarithm of activity (concentration) of hydrogen ions.

pH = -log([H+])

Now, In the question the concentration of [H+] ions is :

[H^{+}]=1\times 10^{-8}

pH = -log(1\times 10^{-8})

use the relation:

log(10^{-a})=a

pH= -(-8)

pH = 8

Note : <em><u> 1 times 10 to the power of 8 must be" 1 times 10 to the power of -8"</u></em>

If the concentration is

[H^{+}]=1\times 10^{8}

Then pH = -8 , which is not possible . So in that  case the pH calculation is by other method

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2 years ago
ʕ•ᴥ•ʔ Which type of reaction occurs between an acid and a base and results in the formation of a salt and water? ʕ•ᴥ•ʔ
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3 0
3 years ago
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An automobile tire was inflated to a pressure of 24 lb in-2 (1.00 atm = 14.7 lb in-2 ) on a winter’s day when the temperature wa
const2013 [10]

Explanation:

Initial Pressure = 24 lb in-2

Initial Temperature = –5 o C = 268 K (Converting to kelvin temperature)

Final Pressure = ?

Final Temperature =  35 o C = 308 K (Converting to kelvin temperature)

No Change in Volume.

From Gay Lusaac's law; pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature.

P1T1 = P2T2

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There would be a drop in pressure as the temperature increases. Appropriate measures should b taken by regularly gauging the pressure of the tire.

6 0
2 years ago
Modify the given fatty acid so that it represents the 18‑carbon fatty acid designated 18:2(Δ9,12). Draw any double bonds in the
Mekhanik [1.2K]

Answer:

See explanation

Explanation:

In this case, we have to remember the meaning of the nomenclature "18:2Δ9,12".  Where 18 is the <u>number of carbon atom</u>s, 2 is the <u>number of double bonds,</u> and the numbers successive to Δ "delta" the position of the double bonds <u>starting</u> to count from the carboxylic -COOH end of the molecule.

In other words, the main functional group is a <u>carboxylic acid</u>. We have a total of 18 carbons. Additionally, we have 2 double bonds. On carbons 9 and 12.

Lets see figure 1

I hope it helps!

5 0
3 years ago
Suppose that 0.410 mol of methane, CH4(g), is reacted with 0.560 mol of fluorine, F2(g), forming CF4(g) and HF(g) as sole produc
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Answer:

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now to find the heat released we have the formula as

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