The noble gases are relatively unreactive because they have a stable octet of valence electrons.
Thus, they do not tend to undergo reactions in which they will gain or lose valence electrons,
However, <em>only He, Ne, and Ar are inert</em>. Kr and Xe combine with other highly reactive elements to form stable compounds.
Answer:
Explanation:
Answer to Armando is an artist who sells prints of his original paintings. ... This problem has been solved! ... Armando wants to create a function P(x). to model his total profit where x is the number of paintings sold
It changes the boiling point of the water, and it changes the freezing point of the water
<u>Answer:</u> The
for the reaction is -297 kJ.
<u>Explanation:</u>
Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.
According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.
The given chemical reaction follows:

The intermediate balanced chemical reaction are:
(1)

(2)

The expression for enthalpy of the reaction follows:
![\Delta H^o_{rxn}=\frac{[1\times (-\Delta H_1)]+[1\times \Delta H_2]}{2}](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5Cfrac%7B%5B1%5Ctimes%20%28-%5CDelta%20H_1%29%5D%2B%5B1%5Ctimes%20%5CDelta%20H_2%5D%7D%7B2%7D)
Putting values in above equation, we get:

Hence, the
for the reaction is -297 kJ.
Answer:
37.6 grams of pentane
Explanation:
The density given in the CRC of 0.626 g/cm³ will be used to calculate the mass of pentane requred since Density = m/v and m= D x V
Be careful in this kind of questions to check for the units. In this case one has to remember 1 mL equal 1 cm³.
m = 0.626 g/cm³ x 60.0 cm³ = 37.6 g pentane