Answer:
<u>2</u>AgI + <u>1</u>Na₂S ⟶ <u>1</u>Ag₂S +<u>2</u>NaI
Explanation:
silver(I) iodide + sodium sulfide ⟶ silver(I) sulfide + sodium iodide
1. Convert the word equation to a chemical equation:
AgI + Na₂S ⟶ Ag₂S + NaI
2. Put a 1 in front of the most complicated-looking formula (Na₂S?):
AgI + <u>1</u>Na₂S ⟶ Ag₂S + NaI
3. Balance Na:
We have fixed 2 Na on the left. We need 2 Na on the right. Put a 2 in front of NaI.
AgI + <u>1</u>Na₂S ⟶ Ag₂S +<u>2</u>NaI
4. Balance S:
We have fixed 1 S on the left. We need 1 O on the right. Put a 1 in front of Ag₂S.
AgI + 1Na₂S ⟶ 1Ag₂S +2NaI
5. Balance Ag:
We have fixed 2Ag on the right. We need 2 Ag on the left. Put a 2 in front of AgI.
<u>2</u>AgI + <u>1</u>Na₂S ⟶ <u>1</u>Ag₂S +<u>2</u>NaI
Every formula now has a coefficient. The equation should be balanced.
6. Check that atoms balance:
<u>Atom</u> <u>On the left</u> <u>On the right
</u>
Ag 2 2
I 2 2
Na 2 2
S 1 1
The balanced equation is
<u>2</u>AgI + <u>1</u>Na₂S ⟶ <u>1</u>Ag₂S +<u>2</u>NaI
Answer:
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The density of the liquid is 0.2 g/mL.
The mass of the liquid is 6 g.
The volume of the liquid is 30.0 mL.
Density = mass/volume = 6 g/30.0 mL = 0.2 g/mL
Answer:
c. 3.00 M HCl
Explanation:
From dilution formula
C1V1 = C2V2
C1=?, V1= 10.0ml, C= 1.5, V2= 20.0ml
Substitute and Simplify
C1×10= 1.5×20
C1= 3.00M
