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Mumz [18]
3 years ago
5

I dont understand this can someone help me

Mathematics
2 answers:
LiRa [457]3 years ago
8 0

Answer:

B

Step-by-step explanation:

kobusy [5.1K]3 years ago
8 0
The answer is B (10'12)
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Which graph shows a system of equations with no solutions?
podryga [215]

Graph of Parallel lines shows a system of equations with no solutions

Step-by-step explanation:

Consider a set of equations

7x - 2y = 16\\21x + 6y =24

If we solve this both equations using any one of the solving method, (Substitution method) then we will get

7x-2y=16\\7x=16+2y\\x=\frac{16+2y}{7}

substituting the following x in 2nd equation (21x + 6y = 24) We get

21(\frac{16+2y}{7} )+6y=24\\3(16+2y)+6y=24\\48+6y+6y=24\\12y=24-48\\y=-\frac{24}{12} \\y=-2

Put y= -2 in x equation

x=\frac{16+2(-2)}{7}\\ x=\frac{16-4}{7}\\\x=\frac{12}{7} \\x=1.71

Comparing these (x,y) values we can understand that they never meet at a point

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3 years ago
Which of the following fractions is equivalent to 75%
Verdich [7]

Answer:

Where are the fractions?

Step-by-step explanation:

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8 0
2 years ago
Read 2 more answers
What is the solution to the following system of equations 4x + 2 = -2y 6y - 18 = 6x
Pavel [41]

Answer:

The solution to the system of equations are;

x = -4/3

y = 5/3

Step-by-step explanation:

To find the Solution, we would carry the Operation simultaneously.

4x + 2 = -2y .........(i)

6y - 18 = 6x ..........(ii)

First let's rearrange the equations, to make the journey smoother

2y + 4x = -2 ...........(iii)

6y - 6x = 18 ...........(iv)

Let's Multiply equation (III) by 3 so as to have a uniform spot to begin elimination.

3.2y + 3.4x = -2 . 3

6y + 12x = -6............... (v)

Let's subtract equation (v) from equation (iv)

= 0y - 18x = 24

-18x = 24

x = - 24 / 18

x = -4/3

Let's substitute (x = -4/3) in equation (ii), so that we can solve for the value of y:

6y - 18 = 6x

6y - 18 = 6 (-4/3)

6y - 18 = -8

6y = -8 + 18

6y = 10.

y = 10 / 6

y = 5/3

The solution to the system of equations are;

x = -4/3

y = 5/3

8 0
3 years ago
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