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Mumz [18]
3 years ago
5

I dont understand this can someone help me

Mathematics
2 answers:
LiRa [457]3 years ago
8 0

Answer:

B

Step-by-step explanation:

kobusy [5.1K]3 years ago
8 0
The answer is B (10'12)
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Mr. and Mrs. Parker's bed is 2 1/3 yards wide. That also have 2 nightstands that are 22 inches wide. The bedroom wall is 12 1/2
vampirchik [111]
Conversions: to smallest (inches)
n= 22 inches 
b= 2 1/3 yard = 84 inches
t= 12 1/2 feet = 150 inches


total space = t
night stand = n (2n for two nightstands)
bed=b

b+2n has to be < or = to t

84+2(22)=x
84+44=128
128 is < 150

therefore the answer is yes they will fit with 22 inches left over.

3 0
3 years ago
Read 2 more answers
R + 11 + 8r= 29<br> Show answer
____ [38]

Answer:

r=2

Step-by-step explanation:

r + 8 r + 11 = 29

( 1 + 8 ) r + 11 = 29 9 r + 11 = 29

Now we can isolate and solve for r while always keeping the equation balanced: First, subtract 11 from each side of the equation:

9 r + 11 − 11 = 29 − 11

9 r + 0 = 18

9 r = 18

Now we can divide each side of the equation by 9 to get

r : 9 over 9 = 18 under 9

1 r = 2

r = 2

6 0
3 years ago
Read 2 more answers
Subtract 2 hours, 20 minutes from 4 hours, 10 minutes.
Dmitrij [34]
To make it easier convert the times all into minutes. 

2 hours 20 minutes = 120 minutes + 20 minute = 140 minutes 
4 hours 10 minutes = 240 minutes + 10 minutes = 250 minutes 

Then subtract: 

250 minutes - 140 minutes = 110 minutes 

Convert back to hours/minutes: 

110 minute = 1 hour and 50 minutes 
3 0
4 years ago
Read 2 more answers
Which angle is an adjacent interior angle?
Vanyuwa [196]
4 is exterior and 3 is adherent interior angle to angle 4. Adjacent angles are two angles that have a common vertex and a common side but do not overlap. In this case common vertex is N. Common side is LN. Good luck.
7 0
3 years ago
Use the Fundamental Counting Principle to solve.
Vedmedyk [2.9K]

number \: of \: performances = 9 \\ note =  \\ one \: insists \: on \: being \: last \\ number \: of \: flexible \: performances = 9 - 1 = 8 \\  \\ c( \gamma ) = 8P8 \times 1 \\ c( \gamma ) = 8! \\ c( \gamma ) = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 \\ c( \gamma ) = 40320 \: ways

7 0
2 years ago
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