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Keith_Richards [23]
3 years ago
6

Summary

Computers and Technology
1 answer:
Karo-lina-s [1.5K]3 years ago
8 0

Answer:

Replace the comments with:

for(x = 0; x < NUM_CITIES; x++){

      if(inCity == citiesInMichigan[x]){           foundIt = true;}

  }

  if(foundIt){ cout<<"Exists";}

  else{cout<<"Does not exists";}  

 

Explanation:

This iterates through the cities

for(x = 0; x < NUM\_CITIES; x++)\{

This checks if current city in the array matches the city input by the user

if(inCity == citie sIn Michigan[x])\{           foundIt = true; If yes, foundIt is set to true}

  }

If foundIt is true, print "Exists"

if(foundIt){ cout<<"Exists";}

If foundIt is false, print "Does not Exists"

  else{cout<<"Does not exists";}  

<em>See attachment for complete program</em>

Download cpp
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You are a visitor at a political convention with delegates; each delegate is a member of exactly one political party. It is impo
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Answer:

The algorithm is as follows:

Step 1: Start

Step 2: Parties = [All delegates in the party]

Step 3: Lent = Count(Parties)

Step 4: Individual = 0

Step 5: Index = 1

Step 6: For I in Lent:

Step 6.1: If Parties[Individual] == Parties[I]:

Step 6.1.1: Index = Index + 1

Step 6.2: Else:

Step 6.2.1 If Index == 0:

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

Step 7: Else

Step 7.1: Index = Index - 1

Step 8: Print(Party[Individual])

Step 9: Stop

Explanation:

The algorithm begins here

Step 1: Start

This gets the political parties as a list

Step 2: Parties = [All delegates in the party]

This counts the number of delegates i.e. the length of the list

Step 3: Lent = Count(Parties)

This initializes the first individual you come in contact with, to delegate 0 [list index begins from 0]

Step 4: Individual = 0

The next person on the list is set to index 1

Step 5: Index = 1

This begins an iteration

Step 6: For I in Lent:

If Parties[Individual] greets, shakes or smile to Party[i]

Step 6.1: If Parties[Individual] == Parties[I]:

Then they belong to the same party. Increment count by 1

Step 6.1.1: Index = Index + 1

If otherwise

Step 6.2: Else:

This checks if the first person is still in check

Step 6.2.1 If Index == 0:

If yes, the iteration is shifted up

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

If the first person is not being checked

Step 7: Else

The index is reduced by 1

Step 7.1: Index = Index - 1

This prints the highest occurrence party

Step 8: Print(Party[Individual])

This ends the algorithm

Step 9: Stop

The algorithm, implemented in Python is added as an attachment

<em>Because there is an iteration which performs repetitive operation, the algorithm running time is: O(n) </em>

Download txt
5 0
3 years ago
The internet is ________. an internal communication system for businesses a large network of networks a communication system for
uranmaximum [27]

A large network of networks

<h3>What Is a large network?</h3>
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To learn more about the network, refer

to https://brainly.in/question/32165678

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4 0
2 years ago
In a relational database model, a(n) _____ operation pares down a table by eliminating columns according to certain criteria. in
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I guess the correct answer is Project

If thе usеr is intеrеstеd in sеlеcting thе valuеs οf a fеw attributеs, rathеr than sеlеctiοn all attributеs οf thе Tablе (Rеlatiοn), thеn οnе shοuld gο fοr Prοjеct Οpеratiοn.

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Answer:

I can't read that pls reformat, or take picture.

Explanation:

3 0
3 years ago
#5 Multiple Select Which of the following describes a hardware error? Select 3 options.
DENIUS [597]

Answer:

A, E

Explanation:

Hope this is correct

7 0
3 years ago
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