I am not quite sure what the choices are, but the answer
to that problem is:
If p is a positive integer, then p(p+1)(p-1) is always
divisible by “an even number”.
The explanation to this is that whatever number you input
to that equation, the answer will always be an even number. This is due to the
expression p(p+1)(p-1) which always result in a even product.
For example if p=3, then (p+1)(p-1) becomes (4)(2) giving
you a even number.
And if for example if p=2, then (p+1)(p-1) becomes (3)(1)
which gives an odd product, but we still have to multiply this with p therefore
2*3 = 6 which is even product. The outcome is always even number.
<span>Answer: From the choices, select the even number</span>
Answer:
16 cm
Step-by-step explanation:
Answer:
(3, -3)
Step-by-step explanation:
When asked to solve by elimination, you put them on top of one another, like you're going to add it.
10x + 7y = 9
-4x - 7y = 9
See that 7y? You can cancel those out because one is negative, and one is positive. So those are gone. You finish adding the rest of the numbers as usual and solve for x.
6x = 18
x = 3
Take x, and plug it into either equation to find y.
10(3) + 7y = 9
7y = -21
y = -3
(3, -3)
Hope this helped!
A good place to start is to set 
to y. That would mean we are looking for 
to be an integer. Clearly, 
, because if y were greater the part under the radical would be a negative, making the radical an imaginary number, not an integer. Also note that since 
is a radical, it only outputs values from ![[0,\infty]](https://tex.z-dn.net/?f=%20%5B0%2C%5Cinfty%5D%20)
, which means y is on the closed interval: ![[0,120]](https://tex.z-dn.net/?f=%20%5B0%2C120%5D%20)
.
With that, we don't really have to consider y anymore, since we know the interval that is on.
Now, we don't even have to find the x values. Note that only 11 perfect squares lie on the interval , which means there are at most 11 numbers that x can be which make the radical an integer. All of the perfect squares are easily constructed. We can say that if k is an arbitrary integer between 0 and 11 then:
Which is strictly positive so we know for sure that all 11 numbers on the closed interval will yield a valid x that makes the radical an integer.
Answer:
5.8m
Step-by-step explanation:
