Law of sines in a triangle with angles A, B, C and sides a,b,c states that
(sin A)/a =(sinB)/b = (sinC)/c
To use the above ratios, you need at least one angle and one side and one of either an angle or a side. So SSS and AAA don't work
Answer:
It's Option D
Step-by-step explanation:
All of Eduardo's steps are justified.
Answer:
Around 6.65
Step-by-step explanation:
X+ 1/x= 5
⇒ (x+ 1/x)^2= 5^2
⇒ (x+ 1/x)^2= 25
⇒ x^2+ 2(x)(1/x)+ 1/x^2= 25
⇒ (x^2+ 1/x^2)+ 2*1= 25
⇒ x^2+ 1/x^2= 25 -2
⇒ x^2+ 1/x^2= 23
The final answer is 23~
let a non zero number be x
30 times the square root of a non zero number is 30sqrt%28x%29
equal to 8 times the number is 8x
so, we have
30sqrt%28x%29=8x...you can solve for x if you square both sides
%2830sqrt%28x%29%29%5E2=%288x%29%5E2
30%5E2%28x%29=64x%5E2
900x=64x%5E2
64x%5E2-900x=0
x%2864x-900%29=0....use zero product rule
x%2864x-900%29=0 if x=0..this is a solution, but our number should be non zero; so, we need other solution
or if %2864x-900%29=0 => 64x=900=> x=900%2F64=> x=14.0625
so, a non zero number be x=14.0625 and this is your solution
let's check this solution:
30sqrt%28x%29=8x
30sqrt%2814.0625%29=8%2A14.0625
30%283.75%29=112.5
112.5=112.5.....this confirms that our answer is correct .
sorry i messed up there.
