Given:
Diameter of the hole = 30 cm
To find:
The area of the hole.
Solution:
The radius of a circle is always half of the diameter. It is given that the diameter of the hole is 30 cm. So, the radius of the hole is:
Area of a circle is:
Putting 
and in the above formula, we get
Therefore, the area of the hold is 706.5 square cm.
Answer:
f(x)=x(x- a) (x - b) 2 that is the answer good luck
A quadrilatetal with two different pairs of equal and parallel sides.
Answer:
4:10, 2:5 16:40
Step-by-step explanation:
just multiply or divide
Answer:
512x−2+8=18
Step 1: Simplify both sides of the equation.
512x−2+8=18
512x+−2+8=18
(512x)+(−2+8)=18(Combine Like Terms)
512x+6=18
512x+6=18
Step 2: Subtract 6 from both sides.
512x+6−6=18−6
512x=12
Step 3: Divide both sides by 512.
512x512=12/512
x= 3/128
Answer:
x=3/128
