Answer:
The minimum number of miles you would need to drive in a month to make the first deal a better deal is 66.6 miles.
Step-by-step explanation:
For the first deal to be a better deal it has to cost less than the second plan and you can write an equation in which the first plan has a lower cost than the second one:
10+0.60m<0.75m, where:
m is the number of miles driven
Now, you can solve for m:
10<0.75m-0.60m
10<0.15m
10/0.15<m
m>66.6
According to this, the answer is that the minimum number of miles you would need to drive in a month to make the first deal a better deal is 66.6 miles.
Approximately 2945.24 units
Answer:
(x+2) (5x)
Step-by-step explanation:
the way I factor is the products of a*c added together equals b. so the products if (5*2) 10 equals 11. so 10 and 1 are the 2 products that add into 11. Now we put that into the equation. 5x^2+10x+1x+2 now take the two haves until you can't factor them any more 5x(x+2) (x+2). now take the repeated factor and outside factors to get (5x) and (x+2)
Answer:
13 months
Step-by-step explanation:
x is the number of months
first phone:
f(x) = 55x + 100
second phone:
g(x) = 51x + 150
now set up the inequality
g(x)<f(x)
51x + 150 < 55x + 100
Solve the inequality:
51x + 150 < 55x + 100
(get everything on the correct sides... combine the like terms)
51x - 55x < 100 - 150
-4x < -50
divide both sides by -4 (don't forget to flip the inequality sign when dividing by a negative number.)
x > 50/4
x > 12.5
round up to 13
It can also be 5(x^2) +2=45
