3 years ago

Solve the expression:

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

3 0

Answer:

3*2+4=6+4=10 and 4*6+6-10=24+6-10=30-10=30

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grin007 [14]

20/4 = 5

40/8 = 5

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80/16 = 5

Answer is 5

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3 years ago

Read 2 more answers

Hi! I need help with the attached question in calc. Thank you:)

Elena L [17]

Answer:

3π square units.

Step-by-step explanation:

We can use the disk method.

Since we are revolving around AB, we have a vertical axis of revolution.

So, our representative rectangle will be horizontal.

R₁ is bounded by y = 9x.

So, x = y/9.

Our radius since our axis is AB will be 1 - x or 1 - y/9.

And we are integrating from y = 0 to y = 9.

By the disk method (for a vertical axis of revolution):

$\displaystyle V=\pi \int_a^b [R(y)]^2\, dy$

So:

$\displaystyle V=\pi\int_0^9\Big(1-\frac{y}{9}\Big)^2\, dy$

Simplify:

$\displaystyle V=\pi\int_0^9(1-\frac{2y}{9}+\frac{y^2}{81})\, dy$

Integrate:

$\displaystyle V=\pi\Big[y-\frac{1}{9}y^2+\frac{1}{243}y^3\Big|_0^9\Big]$

Evaluate (I ignored the 0):

$\displaystyle V=\pi[9-\frac{1}{9}(9)^2+\frac{1}{243}(9^3)]=3\pi$

The volume of the solid is 3π square units.

Note:

You can do this without calculus. Notice that R₁ revolved around AB is simply a right cone with radius 1 and height 9. Then by the volume for a cone formula:

$\displaystyle V=\frac{1}{3}\pi(1)^2(9)=3\pi$

We acquire the exact same answer.

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3 years ago

How do I solve 4^-3? ( four to the power of negative three)

Liono4ka [1.6K]

4^-3

You first need to make the exponent positive. To do this put it in a fraction.

1/4^3

Now solve the exponent.

4 * 4 * 4 =
^
16*4 = 64

1/64 is your answer

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3 years ago

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topjm [15]

Answer:

16 i think

Step-by-step explanation:

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3 years ago

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frosja888 [35]

Answer: