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3 years ago

100 POINT QUESTION!! there's an attachment! :)

Mathematics

2 answers:

Sati [7]3 years ago

4 0

√10 units | √29 units

3,4 and 2,1 | 3,7 and 5,2

-2,3 and 1,2 | 5,-2 and 3,3

-4,-2 and -3,1 | 4,-1 and -1,1

Yanka [14]3 years ago

3 0

Answer:

Square root of 10: (3,4) and (2,1), (-2,3) and (1,2), (-4,-2) and (-3, 1)

Square root of 29: (3,7) and (5,2), (5,-2) and (3,3), (4,-1) and (-1,1)

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Which of the following is the simplified

Umnica [9.8K]

Answer:

C. 8a - 36

Step-by-step explanation:

a + 3a - 4(9-a)

a + 3a - 36 + 4a

8a - 36

4 0

2 years ago

Read 2 more answers

The issue of corporate tax reform has been cause for much debate in the United States. Among those in the legislature, 27% are R

Ilia_Sergeevich [38]

Answer:

The probability Democrat is selected given that this member favors some type of corporate tax reform is 0.6309.

Step-by-step explanation:

Let us suppose that,

R = Republicans

D = Democrats

I = Independents.

X = a member favors some type of corporate tax reform.

The information provided is:

P (R) = 0.27

P (D) = 0.56

P (I) = 0.17

P (X|R) = 0.34

P (X|D) = 0.41

P (X|I) = 0.25.

Compute the probability that a randomly selected member favors some type of corporate tax reform as follows:

$P(X)=P(X|R)P(R)+P(X|D)P(D)+P(X|I)P(I)\\= (0.34\times0.27)+(0.41\times0.56)+(0.25\times0.17)\\=0.3639$

The probability that a randomly selected member favors some type of corporate tax reform is P (X) = 0.3639.

Compute the probability Democrat is selected given that this member favors some type of corporate tax reform as follows:

$P(D|X)=\frac{P(X|D)P(D)}{P(X)} =\frac{0.41\times0.56}{0.3639}=0.6309$

Thus, the probability Democrat is selected given that this member favors some type of corporate tax reform is 0.6309.

5 0

3 years ago

Sin5A/SinA-cos5A/cosA=4cos2A

irina1246 [14]

Answer:

See Explanation

Step-by-step explanation:

$\frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} = 4\cos2A \\ \\ LHS = \frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} \\ \\ = \frac{ \sin5A \:\cos A - \cos5A \: \sin A}{\sin A \:\cos A } \\ \\ = \frac{ \sin(5A -A )}{\sin A \:\cos A} \\ \\ = \frac{ \sin 4A}{\sin A \:\cos A} \\ \\ = \frac{ 2\sin 2A \: \cos 2A}{\sin A \:\cos A} \\ \\ = \frac{ 2 \times 2\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A} \\ \\ = \frac{ 4\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A} \\ \\ =4\cos 2A \\ \\ = RHS \\ \\ thus \\ \\ \frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} = 4\cos2A \\ \\ hence \: proved$

5 0

3 years ago

she brought 7/8 as much in april as she did in october and july combined october has 3/4 and july has 1 and 1 fourth

Leno4ka [110]

What's the question?

4 0

3 years ago

Antonette gets $70\%$ on a 10-problem test, $80\%$ on a 20-problem test and $90\%$ on a 30-problem test. If the three tests are

notka56 [123]

Answer:

Percentage score will be 83.33 %

Step-by-step explanation:

We have given Antonette gets 70 % on 10 problem test

Let consider here here total problem = total marks

So marks get 10 10 problem test = 10×0.7 = 7

Marks get in 20 problem test = 20×0.8 = 16

And marks get in 30 problem test = 30×0.9 = 27

Now total marks get get by Antonette = 7 +16 + 27 = 50

And total marks = 60

So percentage score of Antonette $=\frac{50}{60}\times 100=83.33$ %

8 0

3 years ago