Answer:
B
Step-by-step explanation:
The first quartile of his data is 60.
The median of his data is 82.
The first quartile Q1 is the median of the lower half of the data set. This means that about 25% of the numbers in the data set lie below Q1 and about 75% lie above Q1.
The median Q2 is the median of the data set. This means that about 50% of the numbers in the data set lie below Q2 and about 50% lie above Q2.
Between Q1 and Q2 lie exactly 25% of the numbers in the data set.
25% of 200 is exactly 50, so option B is true.
164+56−(3+4+1)
=220−(3+4+1)
=220−(7+1)
=220−8
=212
Answer:
Step-by-step explanation:
(285)=13p+108
177=13p
p= 13.62 lbs
Answer: masses are 825 g and 1125 g
Step-by-step explanation: masses of hamsters are x and x+ 300 g.
Total mass is x+(x+300) = 1950
2x = 1650 g and x= 825
Answer:
14.7 quarts
Step-by-step explanation:
Use the given equivalence figures to write a proportion. Solve the proportion for the unknown value.
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quarts/liters = x/14 = 1/0.95 . . . . . the conversion is given as 1 qt = 0.95 L
Multiply by 14 to find x.
x = 14(1/0.95) ≈ 14.7
There are about 14.7 quarts in 14 liters.
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<em>Additional comment</em>
You are given a value in liters (14 liters) and asked for the equivalent in quarts. That means you want to change the units from liters to quarts. To do that, you can multiply the given value (14 liters) by a conversion factor that has quarts in the numerator and liters in the denominator. That is what the fraction 1/0.95 is in the above. You will note that units of liters cancel in this equation.

This rule, "use a conversion factor that divides by the units you don't want and multiplies by the units you do want" applies to any units conversion problem. The conversion factor you use should <em>always</em> have <em>equal quantities</em> in the numerator and denominator. (Here, the equal quantities are 1 quart and 0.95 liters.)
You will notice that we treat units just like any variable. They can be multiplied, divided, cancelled, raised to a power. Only terms with like units can be added or subtracted.