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Nuetrik [128]
3 years ago
6

How can we classify the group of elements by just looking at its valence configuration?

Chemistry
1 answer:
Marina86 [1]3 years ago
3 0

Electron configurations

Valence electrons are electrons used in forming bonds and are in the outer shell of an element.  

The bond that occurs can be either an ionic bond or a covalent bond  

Valence electron determination using electron configurations.  

The main group elements usually have valence electron configurations in the s and p subshells  

While the transition elements in the subshells (n-1) d  

Further explanation

The location of the elemental groups in the periodic system is determined by the number of valence electrons filling the last sub-shell  

The period of an element is determined from the valence shell (the biggest main quantum number (n) )

In an atom, there are levels of energy in the shell and subshell  

This energy level is expressed in the form of electron configurations.  

Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub-shells in the shell of an atom, namely s, p, d, and f. The maximum number of electrons for each subshell is  

s: 2 electrons  

p: 6 electrons  

d: 10 electrons and  

f: 14 electrons  

Charging electrons in the subshell uses the following sequence:  

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.  

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99<br> 96<br> 040Zr<br> +<br> 42He<br> ----&gt;<br> + "42Mo
Ahat [919]

he mass defect of the helium nucleus ⁴He₂ is 0.030377 u

Further explanation

Mass defect means the difference between the mass of particles forming an atom with an atomic mass.

Δm = mass defect ( u )

mp = mass of proton ( u )

me = mass of electron ( u )

mn = mass of neutron ( u )

M = atomic mass ( u )

A = mass number

Z = atomic number

Let us now tackle the problem !

Given :

Unknown :

Δm = ?

Solution :

Learn more

Rutherford’s major achievements : brainly.com/question/1552732

Unit of radius of an atom : brainly.com/question/1968819

Fusion : brainly.com/question/11395223

Answer details

Grade: College

Subject: Physics

Chapter: Nuclear Physics

Keywords: Mass , Defect , Nucleon , Number , Atomic , Proton , Electron , Neutron

4 0
3 years ago
Aluminum oxide (Al2O3) occurs in nature as a mineral called corundum, which is noted for its hardness and resis- tance to attack
Neko [114]

Answer:

7.03×10²³ atoms of Al

Explanation:

Corundum density = 3.97g/cm³

Corundum = Al₂O₃. Then, you have 2 moles of Al and 3 moles of O in 1 mol of the compound.

Let's determine the mass of corundum, by density

Corundum density = Corundum mass / Corundum volume

3.97 g/cm³ = Corundum mass / 15cm³

3.97 g/cm³ . 15cm³ = Corundum mass →59.55 g

Now, let's find out how many moles are in that mass of corundum

1 mol of Al₂O₃ weighs 101.96 g/mol

Then, 101.96 grams of oxide have 2 moles of Al

59.55 g of oxide, will have (59.55  .2)/101.96 = 1.17 moles

Now, we can know the quantity of atoms, by this rule of three

1 mol has NA atoms (6.02×10²³)

1.17 moles will have (1.17  . NA) = 7.03×10²³ atoms of Al

5 0
3 years ago
Drop the insta babes :)​
bezimeni [28]
I’m a dude bruv I mean if u into that
3 0
3 years ago
Read 2 more answers
If an ice cube melts at 0oC but water also freezes at 0oC, what is the difference between melting and freezing in terms of (a) t
zalisa [80]
The energy involved in melting in freezing is heat, At 0 degrees Celsius ice is at an equilibrium where the heat energy absorbed during melting (endothermic) and heat energy dispersed during freezing (exothermic). When ice melts its absorbs heat energy to change states, when water freezes to ice it dispersed heat energy so that the particles can move slow enough to be almost frozen, but still very small vibrations throughout the ice. Particles in the frozen state are packed tightly and help together by a crystal lattice and IMF's, liquid is free flowing with free floating particles that can move freely from one another particle. 
6 0
3 years ago
Calculate the pH of a 0.50 M HIO. The Ka of hypoiodic acid, HIO, is 2.3x10–11.0.305.325.479.474.80
never [62]

Answer:

pH = 5.47

Explanation:

The equilibrium that takes place is:

HIO ↔ H⁺ + IO⁻

Ka = \frac{[H+][IO-]}{[HIO]} = 2.3 * 10⁻¹¹

At equilibrium:

  • [HIO] = 0.5 M - x
  • [H⁺] = x
  • [IO⁻] = x

<u>Replacing those values in the equation for Ka and solving for x:</u>

Ka=\frac{x^2}{0.5-x}=2.3*10^{-11} \\x^2=(2.3*10^{-11})(0.5-x)\\x^2=1.15*10^{-11}-2.3*10^{-11}x\\x^2+2.3*10^{-11}x-1.15*10^{-11}=0\\x=3.39*10^{-6}

Then [H⁺]=3.39 * 10⁻⁶, thus pH = 5.47

7 0
3 years ago
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