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zhenek [66]
3 years ago
6

Can someone please answer this for me please thank you so mucn

Mathematics
1 answer:
Papessa [141]3 years ago
3 0

Answer:

gdhridkdndhhddjndnoudgbdndkkdjdndxkdk

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The sum of three numbers is 131. The second of three numbers is seven more than twice the first. The third number is 12 less tha
Norma-Jean [14]
First number is (x).
Second number is (2x+7).
Third number is (x-12).
Their sum is  (x+2x+7+x-12).
x+2x+7+x-12 =131

You can simplify this equation
4x-5=131,

4x=136
x=136/4=34 (first number), 
(2x+7)=34*2+7=75 (second number)
34-x=34-12 =22(third number)

Check: 34+75+22=131
6 0
3 years ago
2 out of every 7 get accepted you accept 630 how many applied
Naddik [55]
2/7 = 630/x

2x = 7 × 630

2x = 4410

÷ 2

2205 = x

2205 applied
5 0
3 years ago
I really need help with this question ​
bogdanovich [222]

Step-by-step explanation:

∠1 = ∠4 = 57° (vertical angles)

∠6 = 123° (same side interior angles are supplementary)

4 0
3 years ago
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What is the approximate perimeter of the triangle? Use the law of sines to find the answer
ryzh [129]

Answer:

It's 9.2 units    

8 0
3 years ago
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Help please..
kiruha [24]

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C

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