Question

At the circus, a clown is shot from a cannon. This situation can be modeled by the function: h = – 16t2 + 45t + 15, where 'h' is height in feet and 't' is time in seconds. What is the maximum height of the clown?
A. 45 Feet
B. 109. 4 Feet
C. 72.3 Feet
D. 87.3 Feet

Answer 1

Answer:

The maximum height is 46.64 feet.

Step-by-step explanation:

If we take the derivative of h whit respect to t and equal this to zero we would find the value of t which corresponds to the maximum h.

So, we have the function h(t):

$h(t)=-16t^{2} + 45t + 15$

Taking the derivative, we have:

$\frac{dh(t)}{dt}=-32t + 45=0$

Now, we solve it for t:

$t=\frac{45}{32}=1.4\: s$

Finally, we put this value of t into the original equation.

$h(t)=-16(1.4)^{2} + 45(1.4) + 15$

$h_{max}=46.64\: ft$      

Therefore, the maximum height is 46.64 feet. All the given options are wrong, the one that comes closest is option A.

I hope it helps you!