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3 years ago

Find this quotient. -36.86 ______ -3.8 The quotient is:

Mathematics

1 answer:

VMariaS [17]3 years ago

8 0

Answer:

9.7

Step-by-step explanation:

First convert the numbers into whole numbers by multiplying both numbers by 100. Then divide the numbers by using long division.

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What is the equation of the line that passes through the point 4, -6 and has a slope of -3

zheka24 [161]

Y = mx + b. Use this equation for most linear functions. Enter the information that is given to you.
$- 6 = - 3(4) + b$
Multiply the -3 and 4 to get 12.
$-6 = - 12 + b$
Now divide the -12 from both sides.
$\frac{ - 6}{ - 12} = \frac{ - 12}{ - 12} + b$
-12 cancels out on the right side and your left with
$- \frac {1}{2} = b$
Now re-enter the info back into the formula.
$y = - 3x - \frac{1}{2}$
Then you've got your formula

4 0

3 years ago

In the distribution, the first quartile,median and mean are 30.8,48.5 and 42.0 respectively. If the co efficient skewness is -0.

finlep [7]

Answer:

The third quartile is 56.45

Step-by-step explanation:

The given parameters are;

The first quartile, Q₁ = 30.8

The median or second quartile, Q₂ = 48.5

The mean, $\bar x$ = 42.0

Coefficient of skewness = -0.38

The Bowley's coefficient of skewness (SK) is given as follows;

$SK = \dfrac{Q_3 + Q_1 - 2 \times Q_2}{Q_3 - Q_1}$

Plugging in the values, we have;

$-0.38 = \dfrac{Q_3 + 30.8 - 2 \times 48.5}{Q_3 - 30.8}$

Which gives;

-0.38×(Q₃ - 30.8) = Q₃ + 30.8 - 2 × 48.5

11.704 - 0.38·Q₃ = Q₃ - 66.2

1.38·Q₃ = 11.704 + 66.2 = 77.904

Q₃ = 56.45

The third quartile = 56.45.

5 0

3 years ago

Please help solve h(t) =-16t^2+40t+20<br>

gtnhenbr [62]

Answer: el último

Step-by-step explanation:

5 0

2 years ago

What is the slope of this line?

Llana [10]

Answer:

-3/2

Step-by-step explanation:

you can use the rise over run method to find the slope of this line

7 0

2 years ago

Express these numbers in standard form: 1) 35.18 * 1000000; 2) 0.00000235 / 1000000

Julli [10]

Equivalent of fractions using decimals

5 0

2 years ago