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3 years ago

Find this quotient. -36.86 ______ -3.8 The quotient is:

Mathematics

1 answer:

VMariaS [17]3 years ago

8 0

Answer:

9.7

Step-by-step explanation:

First convert the numbers into whole numbers by multiplying both numbers by 100. Then divide the numbers by using long division.

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explain the pattern used to find an answer when you multiply or divide a whole number by a power of 10

scoray [572]

When you multiply or divide a whole number by a power of ten just add the zeros. 5 to the 100000 power is 500000. Five zeros. Hope this helps. Just a little trick and pattern I noticed which helps. :)

8 0

3 years ago

Juan and his little brother Miquel ran around a circular track together. Juan ran on the inner track, which has a radius of 30 f

MArishka [77]

Answer:

he would have had to run 20 more feet then Juan

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Solve the triangle that has a=4.6, B=19°, A=92° (picture provided)

kolezko [41]

Answer:

Option b

Step-by-step explanation:

To solve this problem use the law of the sines.

We have 2 angles of the triangle and one of the sides.

$a = 4.6\\B = 19\°\\A = 92\°\\C = 180 -A - B\\C = 180 - 92 - 19\\C = 69\°$

The law of the sines is:

$\frac{sin(A)}{a} = \frac{sin(B)}{b} = \frac{sin(C)}{c}$

Then:

$\frac{sin(92)}{4.6} = \frac{sin(19)}{b}\\\\b = \frac{sin(19)}{\frac{sin(92)}{4.6}}\\\\b = 1.5$

$\frac{sin(B)}{b} = \frac{sin(C)}{c}\\\\\frac{sin(19)}{1.5} = \frac{sin(69)}{c}\\\\c = \frac{sin(69)}{\frac{sin(19)}{1.5}}\\\\c = 4.30$

8 0

2 years ago

Which inequality will have a solid boundary line and a shaded region above its graph? x − y ≥ 3 2x − 3y ≤ 3 3y − x < 2 2x + y

LenKa [72]

<span>x − y ≥ 3 ... > stands for above on a graph, and the line under it _ stands for shaded.</span>

7 0

3 years ago

Factor completely. 12x4+18x3+45x2 Enter your answer in the box.

lukranit [14]

QUESTION 1

The given expression is

$12x^4+18x^3+45x^2$

The greatest common factor is $3x^2$ .

We factor to obtain;

$3x^2(4x^2+6x+15)$

QUESTION 2

The given quadratic equation is

$x^2+6x-72=0$

We split the middle term to obtain

$x^2+12x-6x-72=0$

Factor by grouping;

$x(x+12)-6(x+12)=0$

$(x+12)(x-6)=0$

Use zero product property;

$(x+12)=0\:\:or\:\:(x-6)=0$

$x=-12\:\:or\:\:x=6$

QUESTION 3

The given system of equation is

$3x+4y=-8$

$7x-3y=6$

If we multiply $3x+4y=-8$ by 3, we obtain;

$9x+12y=-24$

If we multiply $7x-3y=6$ by 4 we obtain;

$28x-12y=24$

Adding the last two equations will give us;

$37x=0$

The y-variable is eliminated.

Answer:Multiply 3x+4y=−8

by 3. Multiply 7x−3y=6 by 4. Add the resulting equations together.

6 0

3 years ago