1. Jamar writes 5 -(-6). 4+(-3) = 41. Elena says the result should be

PLEASEE SHOW WORK ON ALL (except #3 but also answer :D) 10 POINTS EACH QUESTION SO 50 POINTS + BRAINLY

Phantasy [73]

Grade level is this??

6 0

3 years ago

The American Water Works Association reports that the per capita water use in a single-family home is 63 gallons per day. Legacy

Debora [2.8K]

Answer:

$t=\frac{60-63}{\frac{8.9}{\sqrt{28}}}=-1.784$

$df=n-1=28-1=27$

$p_v =P(t_{(27)}$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is less than 63 gallons per day at 1% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=60$ represent the sample mean

$s=8.9$ represent the sample standard deviation

$n=28$ sample size

$\mu_o =68$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is less than 63, the system of hypothesis would be:

Null hypothesis: $\mu \geq 63$

Alternative hypothesis: $\mu < 63$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{60-63}{\frac{8.9}{\sqrt{28}}}=-1.784$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=28-1=27$

Since is a one side lower test the p value would be:

$p_v =P(t_{(27)}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is less than 63 gallons per day at 1% of signficance.

5 0

3 years ago

an aquarium holds 33.75 gallons of water. it has a length of 2 feet and a height of 1.5 feet what is the width of the aquarium

kolezko [41]

33.75 = 2*1.5*x
33.75 = 3x
x = 11.25 feet

6 0

3 years ago

Read 2 more answers

A weather forecaster says the temperature will be about-5C “give or take” 10 degrees. What is the greatest possible temperature?

IRINA_888 [86]

The greatest possible temperature is $5^{\circ} \mathrm{C}$ and least possible temperature is $-15^{\circ} \mathrm{C}$

<u>Solution:</u>

Given that according to weather forecaster the temperature will be about -5 degree celsius given or take 10 degree”

Need to determine greatest possible temperature and least possible temperature.

Give and take in given statement means a temperature can go up by 10 degrees and can go down by 10 degrees

So greatest possible temperature will be $-5^{\circ} \mathrm{C}+10^{\circ} \mathrm{C}=5^{\circ} \mathrm{C}$

Least possible temperature will be $-5^{\circ} \mathrm{C}-10^{\circ} \mathrm{C}=-15^{\circ} \mathrm{C}$

Hence according to weather forecaster, greatest possible temperature = $5^{\circ} \mathrm{C}$ and least possible temperature = $-15^{\circ} \mathrm{C}$

4 0

3 years ago

A zoo has 2 male lions one sixth oh the lions are male lions how many lions are there at the zoo ?

Deffense [45]

I'm guessing there are 12 lions since half of twelve is 6 and there is only 2 male lions. I would put down 12. Hope that helps!

8 0

3 years ago

Read 2 more answers