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Marrrta [24]
3 years ago
10

17.8.1: Writing a recursive math function. Write code to complete raise_to_power(). Note: This example is for practicing recursi

on; a non-recursive function, or using the built-in function math.pow(), would be more common.
Computers and Technology
1 answer:
Yuliya22 [10]3 years ago
6 0

Answer:

The recursion function is as follows:

def raise_to_power(num, power):

if power == 0:

 return 1

elif power == 1:

 return num

else:

 return (num*raise_to_power(num, power-1))

Explanation:

This defines the function

def raise_to_power(num, power):

If power is 0, this returns 1

if power == 0:

 return 1

If power is 1, this returns num

elif power == 1:

 return num

If otherwise, it calculates the power recursively

else:

 return (num*raise_to_power(num, power-1))

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Explanation:

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To create a formula in ___ you would first click in one of the cells. A.word b.excel c.facebook d.powerpoint
guajiro [1.7K]
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6 0
3 years ago
Write a loop that subtracts 1 from each element in lowerScores. If the element was already 0 or negative, assign 0 to the elemen
Verdich [7]

Answer:

Replace <STUDENT CODE> with

for (i = 0; i < SCORES_SIZE; ++i) {

       if(lowerScores.at(i)<=0){

           lowerScores.at(i) = 0;

       }

       else{

           lowerScores.at(i) = lowerScores.at(i) - 1;

       }  

   }

Explanation:

To do this, we simply iterate through the vector.

For each item in the vector, we run a check if it is less than 1 (i.e. 0 or negative).

If yes, the vector item is set to 0

If otherwise, 1 is subtracted from that vector item

This line iterates through the vector

for (i = 0; i < SCORES_SIZE; ++i) {

This checks if vector item is less than 1

       if(lowerScores.at(i)<1){

If yes, the vector item is set to 0

           lowerScores.at(i) = 0;

       }

       else{

If otherwise, 1 is subtracted from the vector item

           lowerScores.at(i) = lowerScores.at(i) - 1;

       }  

   }

Also, include the following at the beginning of the program:

<em>#include <vector></em>

8 0
3 years ago
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