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2 years ago

How do you find a fraction between 1 4/6 and 1 5/6? ILL GIVE BRAINLEST

Mathematics

2 answers:

mezya [45]2 years ago

5 0

Answer:

21/12

Step-by-step explanation:

You can multiply the number: 1 4/6 1 5/6

10/6 and 11/6

20/12 and 22/12

21/12

I think I am not sure, I have not learned it.

Lubov Fominskaja [6]2 years ago

3 0

Answer:

To find a fraction between two fractions, all we need to do is make the sum of the numerators be the new numerator, and the sum of the denominators be the new denominator. then write down the number of rational number you want. if you need more then multiply the denominator and numerator by 10,100.

Step-by-step explanation:

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Which of the following are solutions to the equation below (5x+1)^2=7?<br><br> Check all that apply.

stiv31 [10]

(5x+1)² = 7; expand: 25x² + 10x +1 = 7 or 25x² + 10x -6 = 0

Solve this quadratic for x:

x = [-b + √(b² - 4ac)]/2a and x = [-b - √(b² - 4ac)]/2a
Plug the values and you'll find :
x = (- √7 - 1)/5 (answer C)
x = (+√7 -1)/5 (answer E)

4 0

2 years ago

Read 2 more answers

aleksley [76]

Answer:

a=1.66

b=8368.12

Step-by-step explanation:

hope it helps

8 0

2 years ago

The snooze buttonon your alarm clock activates the alarm every 5 minutes. The snooze button on your cell phone activates the ala

Tomtit [17]

Answer: 7:35 a. M

Step-by-step explanation:

Given that:

Snooze on alarm = 5 minutes

Snooze on cellphone = 7 minutes

If both activates at 7:00 a. M

Time at which both will activate again ;

Obtain the Lowest Common Multiple of 5 and 7

_5 __|5 ___|7

_7__ |1 ___|7

____ |1 ___| 1

Lowest common multiple = (5 * 7) = 35

Hence, both alarms will sound together again after 35 minutes = 7:00a.m + 35 minutes = 7:35 A. M

5 0

2 years ago

Which of the following is an improper integral?

guapka [62]

Answer:

A) $\displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx$

General Formulas and Concepts:

<u>Calculus</u>

Discontinuities

Removable (Hole)
Jump
Infinite (Asymptote)

Integration

Integrals
Definite Integrals
Integration Constant C
Improper Integrals

Step-by-step explanation:

Let's define our answer choices:

A) $\displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx$

B) $\displaystyle \int\limits^3_1 {\frac{x + 1}{3x - 2}} \, dx$

C) $\displaystyle \int\limits^0_{-1} {\frac{x + 1}{3x - 2}} \, dx$

D) None of these

We can see that we would have a infinite discontinuity if x = 2/3, as it would make the denominator 0 and we cannot divide by 0. Therefore, any interval that includes the value 2/3 would have to be rewritten and evaluated as an improper integral.

Of all the answer choices, we can see that A's bounds of integration (interval) includes x = 2/3.

∴ our answer is A.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

6 0

2 years ago

A rectangle is graphed on the coordinate grid.

-BARSIC- [3]

C.y=x+9 is the answer

4 0

2 years ago