Answer:
The volume of the concentrated 80 gallons mixture is 20 gallons
The volume of water in the 80 gallons mixture is 60 gallons
Step-by-step explanation:
The given parameters are;
The content of Container A = The cleaner
The concentration of the cleaner = 20% solution
The content of Container B = Pure water
The concentration of the desired solution = 5%
The volume of the required solution = 80 gallons
Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture
Therefore, we have;
20/100 × x + y×0 = 5/100×80
x + y = 80
y = 80 - x
20/100 × x + (80 - x)×0 = 5/100×80
0.2·x = 4
x = 4/0.2 = 20
x = 20 gallons
y = 80 - x = 80 - 20 = 60
y = 60 gallons
The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons
The volume of water in the 80 gallons mixture = y = 60 gallons.
Answer:
1. Q1=7 Q3=12 IQR=5
2. Q1=8 Q3=33 IQR=25
3. Q1=4.5 Q3=10 IQR=5.5
Step-by-step explanation:
hope this helps have a good day or night
Answer:
y = -x + 4
perp: m = 1
y + 4 = x - 3
y = x - 7
Step-by-step explanation:
Step-by-step explanation:
sorry but i need points Thank you
Answer:
29500
Step-by-step explanation:
subtract the two numbers
