The area of any triangle is A = (1/2) (base) (height).
If the right triangle is not sitting
on its hypotenuse, then one leg
is the base, and the other leg is
the height: A = (1/2) (base leg) (height leg) .
If the triangle is isosceles, then
the legs are equal: A = (1/2) (either leg)²
You said the area is 18 in²: 18 in² = (1/2) (leg²)
Multiply each side by 2 : 36 in² = leg²
Square root each side: 6 in = leg
Call this piece of the plane S. Parameterize S by the vector function
s(u, v) = u i + v j + (28 - 2u - 3v)/4 k
with 1 ≤ u ≤ 4 and 2 ≤ v ≤ 6. Take the normal vector to S to be
∂s/∂u x ∂s/∂v = 1/2 i + 3/4 j + k
which has norm √((1/2)^2 + (3/4)^2 + 1^2) = √29/4
The area of S is then
Hey there,
The word problem is as follows:
- 91 is the quotient of c and 283
From the word choice you know that this is a division problem therefore in numbers this would become 283 ÷ c = 91.
Now that we know that in order to find c we would have to divide 283 by 91 which is another way to write that equation.
So...
- 283 ÷ 91 would be 3
Hope I helped,
Amna
Since we are decreasing by 5 each time, we can build up a series formula first.
Now, adding summation notation, we produce: