Answer: Option D
Step-by-step explanation:
Note that the projectile height as a function of time is given by the quadratic equation
To find the maximum height of the projectile we must find the maximum value of the quadratic function.
By definition the maximum value of a quadratic equation of the form
is located on the vertex of the parabola:
Where 
In this case the equation is:
Then
So:
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The slope-intercept form: y = mx + b
m - slope
b - y-intercept
We have 3x - 2y = 6 <em>subtract 3x from both sides</em>
-2y = -3x + 6 <em>divide both sides by -2</em>
y = 3/2 x - 3
slope: m = 3/2
y-intercept: b = -3
x-intercept for y = 0. Substitute:
3/2 x - 3 = 0 <em>add 3 to both sides</em>
3/2 x = 3 <em>multiply both sides by 2/3</em>
x = 2
<h3>Answer:</h3><h3>slope = 3/2</h3><h3>y-intercept = -3</h3><h3>x-intercept = 2</h3>
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y = 3/2 x - 3 it's the same function like first function.
Answer:
the number 151
Step-by-step explanation:
this because if you round 151 to the nearest hundread it would give you 200 but if you round it to the nearest ten ot would give you 150 which is closer to the actual number than 200.
Answer:
the answer is the first one
Step-by-step explanation:
