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Vilka [71]
3 years ago
7

I need help please ASAP

Mathematics
2 answers:
Daniel [21]3 years ago
4 0

Answer:

7

Step-by-step explanation:

8+9=17 -10 = 7

ivann1987 [24]3 years ago
4 0
-33
6-(8+3^3)-4
6-(8+27)-4
6-(35)-4
-29-4
-33
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8x + 5y = 22<br> -8x + y = 14
finlep [7]

Answer:

Y = 6 X=-1

Step-by-step explanation:

  1. Add the numbers 8x+-8x=0. 5y+y=6y. 22+14=36
  2. So that means 6y=36. So Y would equal 6
  3. Substitute the values it one of the original equations. 8x + 5(6) =22. 8x+30=22
  4. Minus 22 from both sides.
  5. That would give you 8x=-8
  6. So x would equal - 1
3 0
3 years ago
Read 2 more answers
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
Help me to do this please
Tanzania [10]

If x represents the mass of 1 ball in kg, then the balance shows ...

... 6x = x + 9 kg

... 5x = 9 kg

Then 6x is ...

... (6/5)·5x = (6/5)·9 kg = 10.8 kg

0.8 kg = 0.8·1000 g = 800 g

so 10.8 kg is ...

... D. 10 kg 800 g

7 0
3 years ago
How can I solve (n+1) x 2= 10 <br> Please someone answer :(
Ray Of Light [21]
(n+1)x 2=10 
2n+2=10 
2n=8
n=4
4 0
4 years ago
Read 2 more answers
If ordered pairs (a, -2) and (4, b) belong to set {(a, b): b=2a-8, find the value of a and b
wel

Answer:

a = 3   b = 0

Step-by-step explanation:

(a,-2)   b= -2

-2=2a -8

6=2a

3=a

(4,b)   a=4

b=2(4)-8

b=8-8

b=0

3 0
3 years ago
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