Solve the initial value problem y'=2 cos 2x/(3+2y),y(0)=−1 and determine where the solution attains its maximum value.
1 answer:
Answer:
Step-by-step explanation:
We are given that
y(0)=-1
Taking integration on both sides then we get
Using formula
Substitute x=0 and y=-1
Substitute the value of C
By using quadratic formula
Hence, the solution
When the solution is maximum then y'=0
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