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Ganezh [65]
3 years ago
13

HELP ME I HAVE MORE QUESTIONS One day, a person went to horse racing area, Instead of counting the number of human and horses, h

e instead counted 74 heads and 196 legs. Yet he knew the number of humans and horses there. How many humans and horses are there?
A.
24 Horses and 50 Humans

B.
20 Horses and 54 Humans

C.
15 Horses and 45 Humans

D.
25 Horses and 55 Humans
WILL GIVE BRIANLEST IF CORRET
Mathematics
2 answers:
Sedbober [7]3 years ago
5 0

Answer:

A

Step-by-step explanation:

Olenka [21]3 years ago
4 0

Answer:

A

Step-by-step explanation:

You know a horse has 4 legs and one head and a human has one head and two legs. Now, if you have 24 horses, then you have 24 heads and 96 legs, because 24*4 is 96. If you have 50 humans, you have 50 heads and 100 legs: 50*2 is 100.

24 heads from horses+50 heads from humans=74 heads

96 legs from horses+100 legs from humans=196 legs

If you try to do this with the other options, you are not going to get 74 heads and 196 legs.

Let's do it with option b: 20 horses and 50 humans

Horses: 20*4=80 legs and 20 heads

Humans: 54*2=108 legs and 54 heads

80 legs from the horses+108 legs from humans=188 legs

54 heads from humans+20 heads from horses=74 heads

Now, you do get 74 heads, but not 196 legs.

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BartSMP [9]

The equation of f(x) is f(x) = x + 4

<h3>How to determine the equation?</h3>

The given parameters are

f(-1) = 3 and f(1) = 5

Start by calculating the slope (m) using:

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This gives

m = \frac{5 - 3}{1 + 1}

Evaluate

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The equation is then calculated as;

f(x) = m(x - x1) + f(-1)

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1 year ago
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Sholpan [36]

Answer: Choice D

b greater-than 3 and StartFraction 2 over 15 EndFraction

In other words,

b > 3 & 2/15

or

b > 3\frac{2}{15}\\\\

========================================================

Explanation:

Let's convert the mixed number 2 & 3/5 into an improper fraction.

We'll use the rule

a & b/c = (a*c + b)/c

In this case, a = 2, b = 3, c = 5

So,

a & b/c = (a*c + b)/c

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2 & 3/5 = (10 + 3)/5

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The inequality 2 \frac{3}{5} < b - \frac{8}{15}\\\\ is the same as \frac{13}{5} < b - \frac{8}{15}\\\\

---------------------

Let's multiply both sides by 15 to clear out the fractions

\frac{13}{5} < b - \frac{8}{15}\\\\15*\frac{13}{5} < 15*\left(b - \frac{8}{15}\right)\\\\39 < 15b-8\\\\

---------------------

Now isolate the variable b

39 < 15b-8\\\\15b-8 > 39\\\\15b > 39+8\\\\15b > 47\\\\b > \frac{47}{15}\\\\b > \frac{45+2}{15}\\\\b > \frac{45}{15}+\frac{2}{15}\\\\b > 3+\frac{2}{15}\\\\b > 3\frac{2}{15}\\\\

Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how

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The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.

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