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Ganezh [65]
3 years ago
13

HELP ME I HAVE MORE QUESTIONS One day, a person went to horse racing area, Instead of counting the number of human and horses, h

e instead counted 74 heads and 196 legs. Yet he knew the number of humans and horses there. How many humans and horses are there?
A.
24 Horses and 50 Humans

B.
20 Horses and 54 Humans

C.
15 Horses and 45 Humans

D.
25 Horses and 55 Humans
WILL GIVE BRIANLEST IF CORRET
Mathematics
2 answers:
Sedbober [7]3 years ago
5 0

Answer:

A

Step-by-step explanation:

Olenka [21]3 years ago
4 0

Answer:

A

Step-by-step explanation:

You know a horse has 4 legs and one head and a human has one head and two legs. Now, if you have 24 horses, then you have 24 heads and 96 legs, because 24*4 is 96. If you have 50 humans, you have 50 heads and 100 legs: 50*2 is 100.

24 heads from horses+50 heads from humans=74 heads

96 legs from horses+100 legs from humans=196 legs

If you try to do this with the other options, you are not going to get 74 heads and 196 legs.

Let's do it with option b: 20 horses and 50 humans

Horses: 20*4=80 legs and 20 heads

Humans: 54*2=108 legs and 54 heads

80 legs from the horses+108 legs from humans=188 legs

54 heads from humans+20 heads from horses=74 heads

Now, you do get 74 heads, but not 196 legs.

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laila [671]
Try using
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4 0
3 years ago
The heights of baby giraffe are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If 100 b
ANEK [815]

Answer:

P(\bar X

And we can solve this using the following z score formula:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we use this formula we got:

z = \frac{63-63.6}{\frac{2.5}{\sqrt{100}}}= -2.4

So we can find this probability equivalently like this:

P( Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(63.6,2.5)  

Where \mu=63.6 and \sigma=2.5

We select n =100. Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We want this probability:

P(\bar X

And we can solve this using the following z score formula:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we use this formula we got:

z = \frac{63-63.6}{\frac{2.5}{\sqrt{100}}}= -2.4

So we can find this probability equivalently like this:

P( Z

4 0
3 years ago
Please help!<br><br>4^x*5^y=20, 4^y*5^x=20^2, x+y=?​
photoshop1234 [79]

Answer:

x + y are either 2 or 4

Step-by-step explanation:

conclusion x + y = 2 OR 4

7 0
3 years ago
Find the coordinates of the midpoint M of the segment with the given endpoints. Then find the distance between the two points. R
Mrac [35]

Answer:

Midpoint (-2,4)

distance nearest tenth = 8.9

The approximate distance = 9

Step-by-step explanation:

Formulas

PQ midpoint = (x2 + x1)/2, (y2 + y1)/2

distance d = sqrt( (x2 - x1)^2 + (y2 - y1)^2 )

Givens

x2 = -4

x1 = 0

y2 = 1

y1 = 7

Solution

M(PQ) = (-4+0)/2, (1 + 7)/2

M(PQ) = -2, 4

The midpoint is -2,4

The distance = sqrt( (4 - 0)^2 + (1 + 7)^2 )

The distance = sqrt(16 + 64)

The distance = sqrt(80)

The distance = 4√5           exactly

The distance = 8.94    

The distance = 8.9            To the nearest tenth

Question 2

The distance is rounded to the nearest whole number which is 9.

6 0
3 years ago
X-5/2 =9 <br><br> solve for x
Liono4ka [1.6K]
 Best Answer:<span>  </span><span>(x - 5)^2 = 9 
x - 5 = ±√9 
x = 5 ± 3 
x = 2, 8</span>
5 0
3 years ago
Read 2 more answers
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