28.4 grams = ? ounces

Find the slope of the line(s) passing through the given points. Then tell whether the line(s) rises, falls, is horizontal, or is

bonufazy [111]

Answer:

21) falls

22) vertical

23) rises

24) rises

25) falls

26) horizontal

27) rises

28) horizontal

29) falls

Step-by-step explanation:

We shall use the slope formula $m=\frac{y_2-y_1}{x_2-x_1}$ to calculate the slopes of the line passing through each pair of point.

21: (3,1), (2,6)

The slope is $m=\frac{6-1}{2-3}$

$\implies m=\frac{5}{-1}=-5$ .

A negative slope means this line falls

22) (-2,5), (-2,4)

The slope is $m=\frac{4-5}{-2- -2}=\frac{-1}{0}$ = undefined

An undefined slope means this line is vertical

23) The given point is (0,8) (2,10)

The slope is $m=\frac{10-8}{2-0}=\frac{2}{2}=+1$

A positive slope means this line rises

24) The points are (-3,-3), (3,1)

The slope is $m=\frac{1--3}{3--3}=\frac{4}{6}=+\frac{2}{3}$

A positive slope means this line rises

25) The points are: (5,0) (6,-2)

Slope: $m=\frac{-2-0}{6-5}=\frac{-2}{1}=-2$

A negative slope means this line falls

26) The points are (-2,-8) , (5,-8).

Slope: $m=\frac{-8--8}{5--2}=\frac{0}{7}=0$

A zero slope means this line is horizontal

27) The points are: (-1,2) , (5,3)

Slope: $m=\frac{3-2}{5--1}=+\frac{1}{6}$

A positive slope means this line rises

28) The points are: $(\frac{1}{2},4)$ , (-1,4)

Slope: $m=\frac{4-4}{-1-\frac{1}{2}}=\frac{0}{\frac{1}{2}}=0$

A zero slope means the line is horizontal

29) The points are: $(4,\frac{1}{2}), (5,\frac{1}{4})$

Slope: $m=\frac{\frac{1}{4}-\frac{1}{2}}{5-4}=-\frac{1}{4}$

A negative slope means this line falls.

6 0

3 years ago

Evaluate using <br> Definite integrals

swat32

Since $[0,4]=[0,1]\cup(1,4]$ , we can rewrite the integral as

$\displaystyle \int_0^1f(t)\;dt + \int_1^4 f(t)\; dt$

Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:

$\displaystyle \int_0^1f(t)\;dt = \int_0^11-3t^2\;dt,\quad \int_1^4 f(t)\; dt = \int_1^4 2t\; dt$

Both integrals are quite immediate: you only need to use the power rule

$\displaystyle \int x^n\;dx=\dfrac{x^{n+1}}{n+1}$

to get

$\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4$

Now we only need to evaluate the antiderivatives:

$\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15$

So, the final answer is 15.

4 0

3 years ago

How far apart are the foci of an ellipse with a major axis of 20 feet and a minor axis of 14 feet?

omeli [17]

The solution for this question is simple. First we need to divide both numbers by 2 which will give us 10 and 7. This is the equation x^2/10^2 + y^2/7^2 = 1sqrt(100-49) = 7.14 (the answer do not have a perfect square root)
Foci are 14.28 units apart

3 0

2 years ago

6^3=6*6*6=<br> Help asap

olasank [31]

Answer:

216

Step-by-step explanation:

6*6=36

36*6=216

8 0

3 years ago

A

kozerog [31]

Answer:

Y E S : )

Step-by-step explanation:

3 0

2 years ago