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Scilla [17]
3 years ago
11

1. A student performed the titration as in this experiment. He transferred a 2.00 mL sample of the

Chemistry
1 answer:
Arturiano [62]3 years ago
7 0

Answer:

The student shouldn't have added water to the acid.

Explanation:

The aim of titration is to standardize an unknown solution. Recall that a standard solution is one whose concentration is known.

After the acid has been prepared, it has a particular concentration. The student should't have diluted it further. The further dilution of a small volume of acid drastically reduces the concentration of the acid to such low value that the H^+ ions present are insufficient to react with the OH^- from base in order to turn the solution to pink.

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How many grams of sodium benzoate, C H CO Na, have to be added to 1.50 L of a 0.0200 M solution of benzoic acid, C H CO H, to ma
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Answer: 2.8275grams

Explanation: A buffer is made btw a weak acid and it salt. In a solution made by dissolving a weak acid in solution, equilibrium is set up btw ionised and unionised ion. For Benzoic acid

C6H5COOH....> C6H5COO- + H+

Ka = [C6H5COO-] [H+]/ [C6H5COOH].......(1)

using Ka = 6.5× 10^-5, [C6H5COOH] = 0.02M. PH= - log[H+] ....> [H+]= 10^-4M.

Putting the values in(1)

[C6H5COO-]= 6.5× 10^-5 × 0.02/ 10^-4

[C6H5COO-] = 0.013M = Molarity of sodium benzoate

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Mole(C6H5COONa) = 0.0195mol

Mass(C6H5COONa) = 0.0195 × Molar mass

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Learn more about carbon dioxide:brainly.com/question/14445045

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