Answer:
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Explanation:
0.0733L of 3.00 M CH3COOH solution is needed to provide 0.220 mol of CH3COOH.
<u>Explanation</u>:
Molarity, M = moles of the molecule / Liter of solution
Therefore, we can work backwards to find the number of litres of solution, if we are given the number of moles
The values are a given as,
The molarity of the solution =3.00M
The final moles = 0.220 moles.
0.220 mol CH3COOH ( 1L / 3.00 mol CH3COOH) = 0.220/3.00
=0.0733L of solution
Explanation:
step 1. an inequality has either a <, <=, >=, or a >.
step 2. 1 < 4 is an inequality.
step 3. the answer is A.
(a) The mass of hydrogen sulfide produced in the reaction is 9.44 g.
(b) Water is the limiting reagent in the given reaction.
<h3>
Mass of hydrogen sulfide produced</h3>
Al2S3 + 6H2O ---> 2Al(OH)3 + 3H2S
mass of water in the reaction = 6(18 g/mol) = 108 g/mol
mass of hydrogen sulfide in the reaction: = 3(34) = 102 g/mol
108 g/mol of H2O ------- > 102 g/mol of H2S
10 of H2O -----------> ?
= 9.44 g
Aluminum sulfide will be completely consumed by the reaction while some fraction of water will remain. Thus, water is the limiting reagent in the given reaction.
Learn more about limiting reagents here: brainly.com/question/26905271
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Answer:
Three.
Explanation:
When counting the number of significant figures in a decimal number, you start counting from the right of the decimal point.
0
.00203
Counting from left to right from the decimal point , there are 5 digits.
However, the zeroes before any natural number is not counted as a significant figure.
0.00
203
Thus, there are
3
significant figures ie. 203.
Note: any other numbers added to the right of
0.00203
is also counted as a significant number.
eg.
0.002031
has 4 significant figures.
eg.
0.002030
has 4 significant figures.
