Find the length of one side.
V = s^3
s = cube root of V
V = 729
s = cube root 729
s = 9
Put this into your calculator as 729^0.333333333
It should bring back 9 or 8.999999 something which means 9.
Net
The net is shown below. You will have to do the labeling. But I can tell you what you should label each face as?
Area of one face = s^2
s = 9
Area of one face = 9*9
Area of one face = 81
So when you draw this, each face should be labeled with 81.
It should have it's units (ft^2) if your marker is picky.
Part C
There are 6 sides.
1 side has an area of 81 ft^2
6 sides have an area of 6*81 = 486 ft^2
My solution to the problem is as follows:
EC = 15 ... draw CF = 6 (radius) ...use Pythagorean theorem to find EF.
EF^2 + CF^2 = EC^2
EF^2 = 15^2 - 6^2 = 189 .... EF = sq root 189
triangle GDE is similar to CFE ... thus proportional
GD / ED = CF / EF
GD / 18 = 6 / (sq root 189)
<span>GD = 108 / (sq root 189)
I hope my answer has come to your help. God bless and have a nice day ahead!
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Assuming the possible digits are from 0-9, there are 10*9*8 possibilities which come out to 720