QUESTION 1
1 answer:
You might be interested in
The limit from 1 to 2 of the given antiderivative is; -0.19865
<h3>What is the Limit of the Integral?</h3>
We are given the antiderivative of f(x) as sin(1/(x² + 1)). Thus, to find the limit from 1 to 2, we will solve as;
⇒ (sin ¹/₅) - (sin ¹/₂)
⇒ 0.19866 - 0.47942
⇒ -0.19865
Complete Question is;
If sin(1/(x² + 1)) is an anti derivative for f(x), then what is the limit of f(x)dx from 1 to 2?
Read more about integral limits at; brainly.com/question/10268976
P = 2x+2(450-x)=900
A = x(450 - x)
A = x(450 - x)
-x² + 450x = A
-x² +450x = A
A is going to be maximum, when x is a vertex.
-(x² - 450x) = A
-(x² - 2*225x+225²) - 225² =A
-(x-225)² -225² = A
Vertex when x=225
Largest are 225(450-225) = 225² = 50625 ft²
The square has a largest area.
A = x(450 - x)
A = x(450 - x)
-x² + 450x = A
-x² +450x = A
A is going to be maximum, when x is a vertex.
-(x² - 450x) = A
-(x² - 2*225x+225²) - 225² =A
-(x-225)² -225² = A
Vertex when x=225
Largest are 225(450-225) = 225² = 50625 ft²
The square has a largest area.