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atroni [7]
3 years ago
14

Solve the compound inequality. 4 x - 6 ≥ −10 or 3 x +5 ≤ −10

Mathematics
1 answer:
mixas84 [53]3 years ago
3 0
Hello : 
<span> 4 x - 6 ≥ −10  .....(1)
 or
 3 x +5 ≤ −10 ....(2)
(1) : 4x </span>≥ -4
   x ≥ -1 
(2) : 3x ≤ -15
x ≤ -5
conclusion : x ≤ -5 or  x ≥ -1 
the set solution is :   ] -∞, - 5 ] ∪<span>[-1,+∞[</span>

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2(6x + 1) - 4(x - 5) = -2
mr_godi [17]

Answer:

x=−3

Step-by-step explanation:

2(6x+1)−4(x−5)=−2

Step 1: Simplify both sides of the equation.

2(6x+1)−4(x−5)=−2

(2)(6x)+(2)(1)+(−4)(x)+(−4)(−5)=−2(Distribute)

12x+2+−4x+20=−2

(12x+−4x)+(2+20)=−2(Combine Like Terms)

8x+22=−2

8x+22=−2

Step 2: Subtract 22 from both sides.

8x+22−22=−2−22

8x=−24

Step 3: Divide both sides by 8.

8x/8=−24/8

8 0
3 years ago
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What is the ones digit of a number if its cube ends in 7
Ostrovityanka [42]

Well, I have never seen a question posed this way, but let's check it out by trial and error.

1^3 = 3

2^3 = 8

3^3 = 27 Hey! There's one. And the ones digit ends in 3.

Let's try another number that ends in 3 and see if it works as well.

13^3 = 2197 Wow. It works again. I never noticed this before, so you taught me something new.

I will test one more.

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3 0
3 years ago
Please help, answer must be in fraction form if possible
yuradex [85]

Answer:

28.875 or 28 7/8

Step-by-step explanation:

pls mark brainliest!

steps:

(23+1/2) + (15+1/8) - (9+3/4) then solve

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solve

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solve

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5 0
2 years ago
Complete the square for each expression. write the resulting expression as a binomial squared. x2-4x ___
Elan Coil [88]
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7 0
3 years ago
In ΔGHI, the measure of ∠I=90°, the measure of ∠G=62°, and GH = 96 feet. Find the length of IG to the nearest tenth of a foot.
alexandr402 [8]

Answer:

45.1feet

Step-by-step explanation:

Given the following

∠I=90°

∠G=62°, and

GH = 96 feet = Hypotenuse

Required

IG = Adjacent side

Using the SOH CAH TOA identity

Cos theta = Adj/hyp

Cos 62 =IG/96

IG = 96cos62

IG = 96(0.4695)

IG = 45.1feet

Hence the length of IG to the nearest tenth is 45.1feet

6 0
2 years ago
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