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2 years ago

5

A metal coin has certain properties that can be measured if the coin were to go from earth to moon the coins will remain the sam

e

1 answer:

PtichkaEL [24]2 years ago

6 0

Answer:

its matter

Explanation:

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Which will cause an increase in the reaction rate between molecules?

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I think it's B. Molecules collide more frequently

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2 years ago

If 3.75 moles of aluminum react, how many moles of sulfur are needed?

aliya0001 [1]

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2 years ago

1. Compound A contains 14 g of nitrogen for each 16 g of oxygen. Compound B contains 14 g of nitrogen for each 32 g of oxygen. W

Sever21 [200]

Answer:

The lowest whole number mass ratio of nitrogen that combines with a given mass of oxygen is 1:1

Explanation:

In compound A, we have 14 g of nitrogen combine with 16 g of oxygen

In compound B, we have 14 g of nitrogen combine with 32 g of oxygen

Therefore, we have

A B

Ratio of molar masses 14:16 14:32

Mass of O that combine with 1 g of N 1.14 2.29

Dividing by the smallest mass ratio 1 2

Therefore the lowest whole number mass ratio at which oxygen and nitrogen can combine = 1:1.

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3 years ago

How many atoms are there in 23g of Na? How would I attempt this question. Thanks

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2 years ago

Read 2 more answers

For the first order process: AB The half-life of A is 62.1 seconds. If a sample of A initially has 250.0 g, what mass (in g) of

Molodets [167]

<u>Answer:</u> The mass of sample A after given time is 99.05 g.

<u>Explanation:</u>

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

We are given:

$t_{1/2}=62.1s$

Putting values in above equation, we get:

$k=\frac{0.693}{62.1}=0.011s^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $0.011s^{-1}$

t = time taken for decay process = 84.2 s

$[A_o]$ = initial amount of the reactant = 250 g

[A] = amount left after decay process = ?

Putting values in above equation, we get:

$0.011s^{-1}=\frac{2.303}{84.2s}\log\frac{250}{[A]}$

$[A]=99.05g$

Hence, the mass of sample A after given time is 99.05 g.

5 0

2 years ago