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FrozenT [24]
2 years ago
14

Question 8 (1 point)

Chemistry
1 answer:
allochka39001 [22]2 years ago
6 0

Answer: The limiting reagent is CO and 8.0 mol Fe will be formed.

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Give the number of significant figures in this number: 40
lubasha [3.4K]
The # 4 is the only significant # in 400.. Trailing 0's r not significant unless there is a decimal.

in 0.7000, there are 4 significant #'s.

8 0
3 years ago
Read 2 more answers
Can you Guys please help me on 14,and 15
jok3333 [9.3K]
14. is a and i think 15. is b
7 0
2 years ago
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A science teacher asked students to calculate the density of a toy block. The mass of the block was 110 grams and the volume of
Kipish [7]

Answer:

13.75

Explanation:

Density is equal to mass divided by volume. 110/8 = 13.75

5 0
3 years ago
What is the molecule shown below?
FrozenT [24]

Answer:

2,3–dimethylpentane

Explanation:

To know which option is correct, we shall determine the name of the compound.

To obtain the name of the compound, do the following:

1. Determine the longest continuous carbon chain. This gives the parent name of the compound.

2. Identify the substituent group attached to the compound.

3. Locate the position of the substituent group by giving it the lowest possible count.

4. Combine the above to obtain the name of the compound.

Now, we shall determine the name of the compound as follow:

1. The longest continuous carbon chain is 5. Thus, the parent name of the compound is pentane.

2. The substituent group attached is methyl (–CH₃)

3. There are two methyl group attached to the compound. One is located at carbon 2 and the other at carbon 3.

4. Therefore, the name of the compound is:

2,3–dimethylpentane

None of the options are correct.

8 0
2 years ago
The density of liquid mercury is 13.69 g/cm^3. How many atoms of mercury are in a 15.0 cm^3 sample? Use "E" for "x10" and use si
balu736 [363]
The formula is  m = D x V
D = <span>13.69 g/cm^3.
</span>V = <span>15.0 cm^3 
the mass of the liquid mercury is m= </span>13.69 g/cm^3 x 15.0 cm^3 = 195g
the molar mass of Hg is 200,
1 mole of Hg = 200g Hg, so #mole of Hg= 195 / 200 = 0.97 mol
but we know that
 1 mole  = 6.022 E23 atoms
0.97 mole=?

6.022 E23 atoms x 0.97 / 1 mole = 5.84 E23 atoms
6 0
3 years ago
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