What is the “B” value in a secant function?

A park is 4.6 miles long and 2.7 miles wide. A:what is the total distance around the park? B:if a racecar drove 50 times around

Vlada [557]

Answer:

A) Total distance around the park is 14.6 miles

B) The total distance drove by racer 730 miles

Step-by-step explanation:

Given as :

The length of park = 4.6 miles

The width of park = 2.7 miles

Let the total distance cover around park = Perimeter of park = P miles

So, Perimeter of rectangular park = 2 × Length + 2 × width

or, P = 2 × 4.6 + 2 × 2.7

I.e P = 9.2 + 5.4

Or, perimeter = 14.6 miles

A ) ∴ Total distance around the park = 14.6 miles

B ) The total distance drove by racer = 50 times around the park

So, The total distance drove by car = 50 × Total distance around the park

∴The total distance drove by car = 50 × 14.6 = 730 miles

Hence A) Total distance around the park is 14.6 miles

B) The total distance drove by racer 730 miles answer

6 0

3 years ago

Find the value of each variable and show which property is used.

mojhsa [17]

7y-2=5y+4
+2 +2
__________
7y= 5y + 6
-5y -5y
__________
2y= 6

Y=3

3x+2=23
3x =21
x= 7

7(3) -2= 5(3)+4
19=19
x=19

3(7)+2=23
23= 23
Y=23

Adding and subtracting property

6 0

3 years ago

Six hundred paving stones were examined for cracks, and 20 were found to be cracked. The same 600 stones were then examined for

spin [16.1K]

Answer:

a) probability that is cracked=1/30 (3.33%)

b) probability that is discoloured = 29/600 (4.83%)

c) probability that is cracked and discoloured = 11/600 (1.83%)

Step-by-step explanation:

assuming that each stone is equally likely to be chosen then defining the events C= the stone is cracked , D= the stone is discoloured , N= the stone is neither cracked or discoloured, then

P(C)= number of favourable outcomes/total number of outcomes = 20 stones/600 stones = 1/30 (3.33%)

P(D)= number of favourable outcomes/total number of outcomes = 29 stones/600 stones = 29/600 (4.83%)

the probability that is discoloured and cracked is P(C∩D) , where

P(C∪D)=P(C) + P(D)-P(C∩D)

and

P(C∪D)= 1- P(N)

thus

1- P(N)=P(C) + P(D)-P(C∩D)

P(C∩D)= P(N)+P(C)+P(D) -1

replacing values

P(C∩D)= P(N)+P(C)+P(D)=562/600 + 20/600 + 29/600 -1= 611/600 -1 = 11/600

thus

P(C∩D)= 11/600 (1.83%)

3 0

3 years ago

What is the height of a solid box that has a mass of 438 g, a destiny of 2.17 g/cm, a length of 40 cm, and a width of 20 cm.

lapo4ka [179]

Answer:

h ≈ 0.25 cm

Step-by-step explanation:

Hi there !

density formula

d = m/V

V = l×w×h

replace

2.17 = 438/(40×20)×h

2.17 = 438/800×h

2.17×800×h = 438

1736h = 438

h = 438/1736

h ≈ 0,25 cm

Good luck !

4 0

3 years ago

Will give Brainliest! if right!

maksim [4K]

The answer is B 36 because the chance of you grabbing a white or black is 12/15 meaning if you pulled 15 marbles, most likely 12 of them are white or black. so, because 15 goes into 45 3 times, you multiply 12/15 by 3 getting 36/ 45 meaning you will mostly pull 26 black or white marbles.

6 0

3 years ago